Django 视图有时路由错误 URL

Django view sometimes routes to wrong URL

我有一个采用这种布局的 Django 项目

在urls.py

from django.contrib import admin
from django.conf.urls import url as path
from mapping import views
urlpatterns = [
    path('admin/', admin.site.urls),
    path('map/', views.Map, name='map'),
    path('address',views.Address_Search,name='address')
]

views.py

from django.shortcuts import render
from django.views.decorators.csrf import csrf_exempt
from django.http import JsonResponse,HttpResponse
import geocoder
import pdb
bingkey='mykey'

def Map(request):
    return render(request,'mapping.html')

@csrf_exempt
def Address_Search(request):
    try:
        address=request.POST.get('fname')
        print(address)
        g = geocoder.bing(address,key=bingkey)
        x,y= g.latlng[1],g.latlng[0]
        print(x,y)
        return JsonResponse({'id': 1,'x': x, 'y': y,'Address': address})
    except Exception as e:
        print(e)
        return render(request,'mapping.html')

在模板中我有一个 mapping.html 其中包含

{% block content %}
<html>
{% load static %}
{% load leaflet_tags %}
{% load bootstrap4 %}
<head>
    {% leaflet_js %}
    {% leaflet_css %}
    {% bootstrap_css %}
    <title>Sals Food</title>
    <style type="text/css">
        #map {width: 100%;height:800px;}
        </style>

    <link rel="stylesheet" type="text/css" href="{% static 'search_bar.css' %}">
    <link rel="stylesheet" href="{% static 'bootstrap-4.0.0-dist/css/bootstrap.css' %}" crossorigin="anonymous">
    <link href="https://fonts.googleapis.com/css?family=Poppins" rel="stylesheet" />

    <script type="text/javascript" src="{% static 'jquery/jquery-3.3.1.min.js' %}" > </script>
    <script type="text/javascript" src="{% static 'dist/leaflet.ajax.js' %}" > </script>
    <script type="text/javascript" src="{% static 'turf/turf.min.js' %}" > </script>
    <script type="text/javascript" src="{% static 'basemaps/leaflet-providers.js' %}" > </script>

    <script>
        function subForm()
        {
          var jsdata = {"fname": $('#fname').val()};
          console.log(jsdata);
          var url = "/address/";
          var jqHdr = $.ajax({
                  async: true,
                  cache: false,
                  type: "POST",
                  url: url,
                  data: jsdata,
                  dataType: "json"
              }).done(function (data, textStatus) {
                  if (data.id == 1)
                  {
                      console.log("Longitude: "+data.x + " Latitude: "+data.y + " Address "+data.Address );
                      $('#map').remove();
                      var t = $("<div id='map'></div>");
                      $("body").append(t);
                      createmap(data.x,data.y,data.Address);
                    }
              });
          }

        function createmap(x,y,address){
            var map = L.map('map');
            map.setView([40.70,-73.90], 11);

            var boros = new L.GeoJSON.AJAX("../static/boros.geojson",{
                onEachFeature: function(feature,layer){
                    layer.bindPopup(feature.properties.boro_name)
                }
            });       
            boros.addTo(map);

            L.marker([y, x]).addTo(map).bindPopup(address);
        
            lyrOSM = L.tileLayer.provider('OpenStreetMap.Mapnik');
            lyrESRIWSM = L.tileLayer.provider('Esri.WorldStreetMap');
            lyrESRITopo = L.tileLayer.provider('Esri.WorldTopoMap');
            lyrESRIImagery = L.tileLayer.provider('Esri.WorldImagery').addTo(map);

            objBaseMaps = {
                "Street - OSM":lyrOSM,
                "Street - ESRI":lyrESRIWSM,
                "Imagery - ESRI Imagery":lyrESRIImagery,
                "Topo - ESRI Topo":lyrESRITopo,
            };
            ctlLayers = L.control.layers(objBaseMaps,{}, {sortLayers:true}).addTo(map);
        }  
      </script>

</head>
<body>
    <div class="s01">
        <form action="/address/" method="post">
          <div class="inner-form">
            <div class="input-field second-wrap">
                <input type="text" id="fname" name="fname" value="Enter a address">
            </div>
            <div class="input-field third-wrap">
              <button class="btn-search" onclick="subForm()" type="button">Search</button>
            </div>
          </div>
        </form>
      </div>
 
</body>
</html>
{% endblock %}

工作原理

用户像这样在 http://localhost:8000/map/ 上输入地址

输入的地址被放入 html POST 请求表单并使用 AJAX 将 POST 请求通过管道传递给 view.py Address_Search.地址经过地理编码,它 returns x、y 和地址返回页面。对于此示例,它运行良好,因为您可以看到输出是正确的。 [3]: https://i.stack.imgur.com/hKYU3.jpg [![在此处输入图片描述][3]][3]

问题

有时我输入了错误的地址或只是随机输入的字母

例如,我刚刚输入 55 water street,这就是返回的内容。它不会在 Address_Search 视图中抛出错误,它会对输入进行地理编码,但由于某种原因它会重定向到 http://localhost:8000/address/ 大多数情况下,如果地址准确,这不会发生,这就是我的原因很困惑。我这里一定有问题...

// 20210120180356
// http://localhost:8000/address/

{
  "id": 1,
  "x": -74.00910186767578,
  "y": 40.70320129394531,
  "Address": "55 water street"
}

地址 api 某处似乎有误。我会在 django 方面深入研究它,看看是什么原因造成的。但是,当该错误被抛出时,您正在使用 render,它将呈现您提供的 html 模板并让页面重定向。由于您正在调用 /address/ 并让页面重定向,因此它会重定向到 url.

您可以将响应更改为 json 响应。我会同时更改 try 和 catch,并包含一个 status 键值对以及您想要的数据。

@csrf_exempt
def Address_Search(request):
    try:
        address=request.POST.get('fname')
        print(address)
        g = geocoder.bing(address,key=bingkey)
        x,y= g.latlng[1],g.latlng[0]
        print(x,y)
        return JsonResponse({'status': 'success', 'data': {'id': 1,'x': x, 'y': y,'Address': address}})
    except Exception as e:
        print(e)
        return JsonResponse({'status': 'error', 'error': e})

您甚至可以稍微清理一下,特别是通过使用一个 JsonResponse:

@csrf_exempt
def Address_Search(request):
    response = {'status': None,
                'data': None,
                'error': None,
               }
    try:
        address=request.POST.get('fname')
        print(address)
        g = geocoder.bing(address,key=bingkey)
        x,y= g.latlng[1],g.latlng[0]
        print(x,y)
        response['status'] = 'success'
        response['data'] = {'id': 1,'x': x, 'y': y,'Address': address}

    except Exception as e:
        print(e)
        response['status'] = 'error'
        response['error'] = e
    return JsonResponse(response)

这可能需要一些清理,因为我只是输入 SO,但这是一般的想法

edit - 此外,这将导致 javascript 方面发生一些变化 - 您需要查找错误状态并进行处理,并从数据值而不是只是返回的对象本身。

编辑 2 - 确保当您按下按钮时表单实际上并未提交(即使您没有明确说明,它也被视为提交按钮)。您可以将 onsubmit="return false;" 添加到表单本身,或者在 jquery 中的 done 方法的末尾添加 return false;