如何在值更改后创建新的顺序标志（在 SQL 中）

Question

我正在尝试根据部分的更改创建一个连续的数字标志。

当学生加入一个部分时，该标志应为 1，并继续为 1，直到部分发生变化。第一次更改时标志应为 2，第二次更改时应为 3，依此类推。

由于某个部分在更改后可能会重复，因此我发现创建理想的结果具有挑战性。

如有任何帮助，我们将不胜感激。

示例数据

create table dbo.cluster_test
(student_id int not null
,record_date date not null
,section varchar(30) null)

insert into cluster_test
(student_id, record_date, section)
values
 (123, '2020-02-06', NULL)
,(123, '2020-05-14', 'A')
,(123, '2020-08-12', 'A')
,(123, '2020-09-01', 'B')
,(123, '2020-09-15', 'A')
,(123, '2020-09-29', 'A')
,(123, '2020-11-02', NULL)
,(123, '2020-11-30', NULL)
,(789, '2020-01-12', NULL)
,(789, '2020-04-12', 'A')
,(789, '2020-05-03', NULL)
,(789, '2020-06-13', 'A')
,(789, '2020-06-30', 'B')
,(789, '2020-07-01', 'B')
,(789, '2020-07-22', 'A')

想要的结果

student_id	record_date	section	flag
123	2020-02-06	NULL	NULL
123	2020-05-14	A	1
123	2020-08-12	A	1
123	2020-09-01	B	2
123	2020-09-15	A	3
123	2020-09-29	A	3
123	2020-11-02	NULL	NULL
123	2020-11-30	NULL	NULL
789	2020-01-12	NULL	NULL
789	2020-04-12	A	1
789	2020-05-03	NULL	NULL
789	2020-06-13	A	2
789	2020-06-30	B	3
789	2020-07-01	B	3
789	2020-07-22	A	4

尝试：

select
 student_id
,record_date
,section
,case when section is not null then row_number() over(partition by student_id, section order by record_date asc)
 end row#
,case when (section is not null) and (lag(section, 1) over(partition by student_id order by record_date asc) is null) then 'start'
      when (lag(section, 1) over(partition by student_id order by record_date asc) is not null) and (section != lag(section, 1) over(partition by student_id order by record_date asc)) then 'change'
 end chk_txt
,case when section is not null then (case when (section is not null) and (lag(section, 1) over(partition by student_id order by record_date asc) is null) then 1
                                          when (lag(section, 1) over(partition by student_id order by record_date asc) is not null) and (section != lag(section, 1) over(partition by student_id order by record_date asc)) then 1
                                          else 0
                                     end)
 end chk_val2
from cluster_test

order by 1, 2

Answer 1

是gap和island问题。您可以按如下方式使用解析函数：

Select student_id, record_date, section,
    Case when section is not null 
        Then sum(case when section is not null and (section <> lgs or lgs is null) then 1 end) 
            over (partition by student_id order by record_date)
    End as flag
From (
    Select student_id, record_date, section,
        Lag(section) over (partition by student_id order by record_date) as lgs
    From cluster_test t
) t
order by student_id, record_date;

db<>fiddle

Answer 2

您可以选择多个 CTE 并获取如下所示的数据：

with cte_studentSection as (
    SELECT student_id, record_Date, section
        , lead(section) over(partition by student_id order by record_date) as nextSection
        , row_number() over (partition by student_id order by record_date) as rnk
    FROM dbo.Cluster_test
    where section is not null
), cte_studentSectionFlag as (
    SELECT Student_id, record_date, section, rnk, 1 as flag
    from cte_studentSection as oc
    where record_date = (SELECT MIN(record_Date) from cte_studentSection where student_id = oc.student_id)
    union all 
    SELECT oc.Student_id, oc.record_date, oc.section,oc.rnk, case when oc.section = cte.section then cte.flag else cte.flag + 1 end
    from cte_studentSection as oc
    inner join cte_studentSectionFlag as cte on cte.rnk + 1 = oc.rnk and oc.student_id = cte.student_id
)
select student_id, record_date, section, flag
from cte_studentsectionflag 
union all
select student_id, record_date, section, null as flag
from dbo.Cluster_test
where section is null
order by student_id, record_date;

student_id	record_date	section	flag
123	2020-02-06	NULL	NULL
123	2020-05-14	A	1
123	2020-08-12	A	1
123	2020-09-01	B	2
123	2020-09-15	A	3
123	2020-09-29	A	3
123	2020-11-02	NULL	NULL
123	2020-11-30	NULL	NULL
789	2020-01-12	NULL	NULL
789	2020-04-12	A	1
789	2020-05-03	NULL	NULL
789	2020-06-13	A	1
789	2020-06-30	B	2
789	2020-07-01	B	2
789	2020-07-22	A	3

如何在值更改后创建新的顺序标志（在 SQL 中）

How to create a new sequential flag after a change in value (in SQL)

sql

tsql

sql-server

gaps-and-islands