无法访问子节点值 JSON

Cannot access child node value JSON

我尝试获取嵌套在 JSON 中的一些数据,我通过向 API 发出请求以创建一个包含键 [=34= 的列表来获得 extendedData.e_ETP["value"] ] 的值为 extendedData.e_ETP["value"].

但是当我尝试访问该值时出现错误:无法访问 Newtonsoft.Json.Linq.JValue 上的子值。

当我在 uri 中指定项目的 id 时,`extendedData.e_ETP 不为 null 它有效。

问题是我想为 LUS_BU 设置一个默认值(如果它为 null)或者使用 extendedData.e_ETP 中的一个(如果有

这是 C# 代码的一部分:

myUri = new Uri("https://ilucca.net/api/v3/users?dtContractStart=since,1900-01-01&dtContractEnd=until,2100-01-01,null&fields=id,firstName,lastName,employeeNumber,personalAccount,userAxisValues,legalEntityID,mail,dtContractEnd,dtContractStart,manager[name],birthDate,seniorityDate,gender,extendedData.e_ETP,extendedData.e_contracttype");
        request = (HttpWebRequest)WebRequest.Create(myUri);
        request.Headers["Authorization"] = "ApiKey";
        try
        {
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();
            Stream dataStream = response.GetResponseStream();
            StreamReader reader = new StreamReader(dataStream);
            s = reader.ReadToEnd();
            reader.Close();
            response.Close();
            rep = JObject.Parse(s);

            salaries = rep["data"]["items"].Where(c => (string)c["name"] != "lad" && (int?)c["legalEntityID"] != 10).Select(c => new T_E_LuccaSalarie_LUS()
            {
                LUS_ETP = (c["extendedData"]["e_ETP"] != null ) ? (string)c["extendedData"]["e_ETP"]["value"] : "1"
            }).ToList();
        }
        catch (WebException ex)
        {
            string exMessage = ex.Message;
            if (ex.Response != null)
            {
                using (StreamReader responseReader = new StreamReader(ex.Response.GetResponseStream()))
                {
                    exMessage = responseReader.ReadToEnd();
                    Console.WriteLine(exMessage);
                }
            }
        }

JSON:

{
  "header": {
    "generated": "2021-01-22T16:12:53.4193558",
    "serverTime": 1395,
    "queryTime": 169,
    "queryCount": 18,
    "principal": "API Integration",
    "processId": 6956
  },
  "data": {
    "items": [
      {
        "id": 6,
        "firstName": "John",
        "lastName": "Doe",
        "employeeNumber": "2",
        "personalAccount": "Z0",
        "userAxisValues_1": {
          "id": 10,
          "name": "FT04 SALES",
          "url": "https://ilucca.net/api/v3/axissections/48"
        },
        "legalEntityID": 1,
        "mail": "random@mail.com",
        "dtContractEnd": "2020-01-30T00:00:00",
        "dtContractStart": "2000-06-18T00:00:00",
        "manager": {
          "name": "John Doe"
        },
        "birthDate": "1959-08-23T00:00:00",
        "seniorityDate": "2010-06-18T00:00:00",
        "gender": "Female",
        "extendedData": {
          "e_ETP": null,
          "e_contracttype": {
            "id": 9556,
            "value": 16
          }
        }
      }
    ]
  },
  "metadata": null
}

如果您需要任何具体细节或对特定点的说明,请随时询问。

如评论中所述,如果 e_ETP 为 null,则它在您的 Json 中显示为 "e_ETP": null。该场景表示令牌是 JValue 类型,值为 null。在积极的情况下,e_ETP 类型是 JObject

使用下面的代码,您可以验证类型并分配 LUS_ETP

的值
LUS_ETP = jObj["data"]["items"][0]["extendedData"]["e_ETP"].GetType() == typeof(JObject) 
               ? jObj["data"]["items"][0]["extendedData"]["e_ETP"]["value"].Value<string>() 
               : "1";