如果标签名称在 R 编程中以 "G" 开头,如何删除列标签
How to remove column labels if the name of the label starts with "G" in R programming
如果标签名称以“G”开头,如何删除列标签
代码:
library(pdftools)
library(data.table)
library(tabulizer)
pdf_file <- "new.pdf"
out2 <- extract_tables(pdf_file, pages =c(89), output = "data.frame")
out2<-as.data.table(out2)
colnames(out2)
实际输出:
"Group.1" "Day.7" "Day.8" "Day.9"
"Group.2" "Day.10" "Day.11", "Day.12"
预期输出:
"Day.7" "Day.8" "Day.9"
"Day.10" "Day.11", "Day.12"
另外,请向我推荐任何其他从 PDF 中提取数据表的 R 包(pdftools 和 tabulizer 除外)
这将删除以 "G"
:
开头的列
result <- out2[, !startsWith(names(out2), "G")]
您可以使用 dplyr::select
:
library(dplyr)
dplyr::select(out2, -starts_with("G"))
如果标签名称以“G”开头,如何删除列标签
代码:
library(pdftools)
library(data.table)
library(tabulizer)
pdf_file <- "new.pdf"
out2 <- extract_tables(pdf_file, pages =c(89), output = "data.frame")
out2<-as.data.table(out2)
colnames(out2)
实际输出:
"Group.1" "Day.7" "Day.8" "Day.9"
"Group.2" "Day.10" "Day.11", "Day.12"
预期输出:
"Day.7" "Day.8" "Day.9"
"Day.10" "Day.11", "Day.12"
另外,请向我推荐任何其他从 PDF 中提取数据表的 R 包(pdftools 和 tabulizer 除外)
这将删除以 "G"
:
result <- out2[, !startsWith(names(out2), "G")]
您可以使用 dplyr::select
:
library(dplyr)
dplyr::select(out2, -starts_with("G"))