第二个循环，游戏无法运行和 Sublime Text 问题

Question

我正在开发一个非常简单的 'game'，玩家可以通过 5 次猜测来猜测一个随机数。

还没有完成，但我运行遇到了几个问题。

这是生成随机数并允许玩家猜测的代码

相关代码：

def GuessLoopFunc(guess):
    import random
    import sys
    import time

    sum_guesses = 0

    rand_num = random.randrange(1, 21)
    print(rand_num) 
#This is just for test purposes to know the correct number and see what happens when I guess the correct number
    while True:

        if guess == rand_num:
            print("You got it right!")
            
        else:
            sum_guesses += 1
            if sum_guesses == 4:
                guess = input("That's incorrect...final guess: ")
                continue

            elif sum_guesses == 5:
                print("Oh no! You lost!")
                while True:
                    replay = input("Do you want to play again: ")
                    if replay == "yes" or replay == "Yes":
                        pass #Temporary while I figure out how to loop back to very start (new random number)
                    elif replay == "no" or replay == "No":
                        print("Goodbye")
                        break
                    else:
                        print("I do not understand what you mean...")
                        continue

                else:
                    guess = input("You got it wrong, guess again: ")
                    continue

正如您在我发表的评论中看到的那样，如果玩家表示他们想再次玩游戏（这样他们会得到一个新的随机数），我希望游戏 return 进入程序的最开始。

此外，由于某种原因，游戏在给出正确答案时没有注册，并不断告诉玩家他的答案不正确...这是调用上述模块的游戏代码:

import sys
import random
import time
from GuessLoop import GuessLoopFunc

print("Hello! Welcome to the guess the number game!")
name_player = input("Please enter your name: ")
print("Hello " + str(name_player) + "!")
play = input("Are you ready to play? ")
if play == "Yes" or play == "yes":
    print("Great! Let's get started...")
elif play == "No" or play == "no":
    print("Too bad...")
    sys.exit()
else:
    print("I do not understand your response...")
    quit1 = input("Do you want to quit? ")
    if quit1 == "yes" or quit1 == "Yes":
        sys.exit()
    elif quit1 == "no" or quit1 == "No":
        print("Great! Let's get started!")
        
    else:
        print("I do not understand your response...quitting.")
        sys.exit()

print("I am going to think of think of a number between 1 and 20...")
print("You will get 5 guesses to guess the number...")

time.sleep(1)

print("Okay, I have a number in mind")
guess = input("What is your guess? ")

GuessLoopFunc(guess)

time.sleep(1)
sys.exit()

最后，当我尝试运行 Sublime Text 中的程序时，它运行没有比“请输入您的姓名：”部分更进一步。如果我填写我的名字并按回车键，没有任何反应......但也没有显示错误消息。所以我每次都求助于在 Python IDLE 中测试程序，但这有点乏味......任何人都知道发生了什么。

Answer 1

您的主要问题是您将用户输入 (a string) 与随机数 (integer) 进行比较 - 它们 永远不会相同 作为 string != int.

解法：

您需要通过 int(text) 函数将用户输入转换为数字。

def getInt(text):
    while True:
        try: 
            n = input(text)
            return int(n)
        except ValueError:  # if the input is not a number try again
            print(f"{n} is not a number! Input a number")

....
guess = getInt("What is your guess?")  # now that is an int
....

您有很多可以简化的重复“yes/no”代码部分：

def YesNo(text):
    '''Ask 'test', returns True if 'yes' was answerd else False'''    
    while True:
        answer = input(text).strip().lower()
        if answer not in {"yes","no"}:
            print("Please answer 'yes' or 'no'")
            continue # loop until yes or no was answered
        return answer == "yes"

这减少了

quit1 = input("Do you want to quit? ")
if quit1 == "yes" or quit1 == "Yes":
    sys.exit()
elif quit1 == "no" or quit1 == "No":
    print("Great! Let's get started!")

至

if YesNo("Do you want to quit? "):
    sys.exit()
else:
    pass # do somthing

并在所有 yes/no 个问题中使用它。

要再玩一次，我会将“你想再玩一次吗”问题移出游戏循环：

# do your name questioning and greeting here
# and then enter an endless loop that you break from if not playing again

while True:

    GuessLoopFunc()  # move the guess input inside the GuessLoopFunk as it has
                     # to be done 5 times anyhow. If you spend 5 guesses or
                     # guessed correctly, print some message and return to here
    if YesNo("Play again? "):
        continue
    else:
        break # or sys.exit()

解决 sublime 问题：Issue with Sublime Text 3's build system - can't get input from running program

第二个循环，游戏无法运行和 Sublime Text 问题

Second loop, game not working and Sublime Text problems

python-3.x

sublimetext3