mut 字符串在循环内重新声明
mut String redeclaration inside loop
我正在阅读 Rust 书,猜谜游戏教程有以下代码:
use rand::Rng;
use std::cmp::Ordering;
use std::io;
use std::io::Write;
fn main() {
let secret_number = rand::thread_rng().gen_range(1, 101);
let mut input = String::new();
loop {
print!("Guess the number I'm thinking of: ");
io::stdout().flush().unwrap();
io::stdin().read_line(&mut input).expect("Failed to read line");
let guess: u32 = match input.trim().parse() {
Ok(num) => num,
Err(_) => continue
};
println!("\nYou guessed: {}", guess);
match guess.cmp(&secret_number) {
Ordering::Less => println!("Too small!"),
Ordering::Greater => println!("Too big!"),
Ordering::Equal => {
println!("You win!");
break;
}
}
}
}
此代码在第一次用户输入后失败。如果我在循环内移动 let mut input = String::new();
声明,那么一切正常......但我想知道为什么我必须这样做,因为 input
的地址被传递到 read_line()
?
还有一件事,为什么我必须使用 std::io::Write
才能使用 io::stdout().flush().unwrap();
,因为我已经在使用 use std::io;
?
io::stdin().read_line(&mut input);
此方法不会覆盖 String
but it appends to the String
. This is why only the first iteration of the loop works but it immediately breaks on the second iteration. If you want to re-use the String
buffer between iterations you need to truncate it before passing it back into read_line
。固定工作示例:
use rand::Rng;
use std::cmp::Ordering;
use std::io;
use std::io::Write;
fn main() {
let secret_number = rand::thread_rng().gen_range(1, 101);
let mut input = String::new();
loop {
print!("Guess the number I'm thinking of:");
io::stdout().flush().unwrap();
input.clear(); // truncate String buffer here!
io::stdin()
.read_line(&mut input)
.expect("Failed to read line");
let guess: u32 = match input.trim().parse() {
Ok(num) => num,
Err(_) => continue,
};
println!("\nYou guessed: {}", guess);
match guess.cmp(&secret_number) {
Ordering::Less => println!("Too small!"),
Ordering::Greater => println!("Too big!"),
Ordering::Equal => {
println!("You win!");
break;
}
}
}
}
And one more thing why do I have to use std::io::Write
in order to use io::stdout().flush().unwrap();
since I'm already using use std::io;
?
我正在阅读 Rust 书,猜谜游戏教程有以下代码:
use rand::Rng;
use std::cmp::Ordering;
use std::io;
use std::io::Write;
fn main() {
let secret_number = rand::thread_rng().gen_range(1, 101);
let mut input = String::new();
loop {
print!("Guess the number I'm thinking of: ");
io::stdout().flush().unwrap();
io::stdin().read_line(&mut input).expect("Failed to read line");
let guess: u32 = match input.trim().parse() {
Ok(num) => num,
Err(_) => continue
};
println!("\nYou guessed: {}", guess);
match guess.cmp(&secret_number) {
Ordering::Less => println!("Too small!"),
Ordering::Greater => println!("Too big!"),
Ordering::Equal => {
println!("You win!");
break;
}
}
}
}
此代码在第一次用户输入后失败。如果我在循环内移动 let mut input = String::new();
声明,那么一切正常......但我想知道为什么我必须这样做,因为 input
的地址被传递到 read_line()
?
还有一件事,为什么我必须使用 std::io::Write
才能使用 io::stdout().flush().unwrap();
,因为我已经在使用 use std::io;
?
io::stdin().read_line(&mut input);
此方法不会覆盖 String
but it appends to the String
. This is why only the first iteration of the loop works but it immediately breaks on the second iteration. If you want to re-use the String
buffer between iterations you need to truncate it before passing it back into read_line
。固定工作示例:
use rand::Rng;
use std::cmp::Ordering;
use std::io;
use std::io::Write;
fn main() {
let secret_number = rand::thread_rng().gen_range(1, 101);
let mut input = String::new();
loop {
print!("Guess the number I'm thinking of:");
io::stdout().flush().unwrap();
input.clear(); // truncate String buffer here!
io::stdin()
.read_line(&mut input)
.expect("Failed to read line");
let guess: u32 = match input.trim().parse() {
Ok(num) => num,
Err(_) => continue,
};
println!("\nYou guessed: {}", guess);
match guess.cmp(&secret_number) {
Ordering::Less => println!("Too small!"),
Ordering::Greater => println!("Too big!"),
Ordering::Equal => {
println!("You win!");
break;
}
}
}
}
And one more thing why do I have to use
std::io::Write
in order to useio::stdout().flush().unwrap();
since I'm already using usestd::io;
?