如何将 txt 文件读取到数组并按升序排序？

Question

我有一个包含 10000 个密码的 txt 文件 it.I 我正在尝试按 length.Here 对密码进行排序是我的功能：

void bubbleSortASC(){
    int n = 9999;
    int i,j ;
    char pw[n];
    char temp;
    FILE* fp;
    fp = fopen("C:\Users\inanm\Desktop\project-work-2018555459\10-million-password-list-top\10000.txt", "r");
    //fgets(pw, n , fp);
    while(!feof(fp)){
        fgets(pw, n , fp);
       //printf("%s",pw);
    }
    for(i = 0; i < n-1;i++) {
        for(j = i+1; j < n; j++){
            if(strlen(pw[i]) > strlen(pw[j])){
                strcpy(temp,pw[i]);
                strcpy(pw[i],pw[j]);
                strcpy(pw[j],temp);
            }
        }
    }
    fclose(fp);
printf("Ascending order of first 10 passwords are : \n");
for (i = 0; i < 10; i++){
        printf("%s ", pw[i]);
    }
     printf("\n");
        
}

我没有错误，但我的输出是 empty.Can 你帮我找出问题所在

Answer 1

这样就可以了


void bubbleSortASC() {
    const int lines = 9999;     //< number of words in the file
    const int max_width = 128;  //< max width of a word

    char pw[lines][max_width];  //< array of words

    FILE* fp;
    fp = fopen("words.txt", "r");
    int curr = 0;
    while (!feof(fp)) {
        fgets(pw[curr++], max_width, fp);
    }
    fclose(fp);

    char* sorted[lines];        //< array of char* will be in a sorted order
    for (int i = 0; i < lines; i++) sorted[i] = pw[i];

    // the bubble sort
    for (int i = 0; i < lines - 1; i++) {
        for (int j = 0; j < lines - i - 1; j++) {
            if (strlen(sorted[j]) > strlen(sorted[j+1])) {
                char* tmp = sorted[j];
                sorted[j] = sorted[j+1];
                sorted[j+1] = tmp;
            }
        }
    }

    printf("Ascending order of first 10 passwords are : \n");
    for (int i = 0; i < 10; i++) {
        printf("%s", sorted[i]);
    }
    printf("\n");

}

如何将 txt 文件读取到数组并按升序排序？

How can I read a txt file to an array and sorting in ascending order?

c

sorting

bubble-sort

txt