[TypeGraphQL]无法确定 GraphQL 输入类型

Question

以下配置出现错误。请告诉我错误的原因和解决方法。

■错误信息

Error: Cannot determine GraphQL input type for 'zzzzzInputs' of 'XxxxxInput' class. Is the value, that is used as its TS type or explicit type, decorated with a proper decorator or is it a proper input value?

■复制环境及方法

1. 克隆
   git clone https://github.com/isoittech/hellpj-type-graphql

2. 执行命令
   npm ci
npm run start

■Application/library堆栈

• 节点.js/Express
• 续集
• sequelize-typescript
• type-graphql

■来源

https://github.com/isoittech/hellpj-type-graphql/blob/master/src/main/graphql/ppppp.resolver.ts

@ObjectType()
export class ZzzzzInput {
    @Field((type) => ZzzzzType)
    zzzzz!: ZzzzzType;
    // @Field()
    // zzzzz!: string;
}

@InputType()
export class XxxxxInput {
    @Field((type) => [ZzzzzInput])
    zzzzzInputs!: ZzzzzInput[];
    // @Field((type) => [String])
    // zzzzzInputs!: string[];
}

@Resolver((of) => Yyyyy)
export class XxxxxResolver {
    @Mutation((returns) => Yyyyy)
    async addXxxxx(@Arg("Xxxxx") XxxxxInput: XxxxxInput): Promise<Yyyyy> {
        const serviceOutput: XxxxxServiceOutputDto = {};

        return Promise.resolve(serviceOutput.addedXxxxx!);
    }
}

■我参考这里编码的

https://typegraphql.com/docs/types-and-fields.html

Answer 1

我通过如下修改解决了我的问题。看'★'.
（又找到了一个，也解决了。）

■来源

// @ObjectType()   // ★  Before
@InputType()       // ★  After
export class ZzzzzInput {
    @Field((type) => ZzzzzType)
    zzzzz!: ZzzzzType;
    // @Field()
    // zzzzz!: string;
}

@InputType()
export class XxxxxInput {
    @Field((type) => [ZzzzzInput])
    zzzzzInputs!: ZzzzzInput[];
    // @Field((type) => [String])
    // zzzzzInputs!: string[];
}

@Resolver((of) => Yyyyy)
export class XxxxxResolver {
    @Mutation((returns) => Yyyyy)
    async addXxxxx(@Arg("Xxxxx") XxxxxInput: XxxxxInput): Promise<Yyyyy> {
        const serviceOutput: XxxxxServiceOutputDto = {};

        return Promise.resolve(serviceOutput.addedXxxxx!);
    }
}

■相关来源

node_modules/type-graphql/dist/schema/schema-generator.js

    static getGraphQLInputType(target, propertyName, type, typeOptions = {}, parameterIndex, argName) {
        let gqlType;
        gqlType = types_1.convertTypeIfScalar(type);
        if (!gqlType) {
            ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
            ★ Finding process below not worked when @ObjectType.
            ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
            const inputType = this.inputTypesInfo.find(it => it.target === type);
            if (inputType) {
                gqlType = inputType.type;
            }
        }
        if (!gqlType) {
            ☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆
            ☆ Finding process below not worked when wrong order in src/index.ts.
            ☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆
            const enumType = this.enumTypesInfo.find(it => it.enumObj === type);
            if (enumType) {
                gqlType = enumType.type;
            }
        }
        if (!gqlType) {
            throw new errors_1.CannotDetermineGraphQLTypeError("input", target.name, propertyName, parameterIndex, argName);
        }
        const { nullableByDefault } = build_context_1.BuildContext;
        return types_1.wrapWithTypeOptions(target, propertyName, gqlType, typeOptions, nullableByDefault);
    }

■另一个问题

在我解决了上面的问题后，又出现了一个问题。错误信息如下：

Error: Cannot determine GraphQL input type for 'zzzzz' of 'ZzzzzInput' class. Is the value, that is used as its TS type or explicit type, decorated with a proper decorator or is it a proper input value?

看schema中的☆-generator.js.
找不到枚举类型 'ZzzzzType'，因此发生错误。
因为 this.enumTypesInfo 不包含 'ZzzzzType'.
因为我在SchemaGenerating过程之后执行了注册Enumtype。
我不得不在下面进行修改。

    // enable Enum
    registerEnumType(ZzzzzType, {
        name: "ZzzzzType",
    });
    const schema = await buildSchema({
        resolvers: [__dirname + "/graphql/*.resolver.ts"],
        emitSchemaFile: true,
        validate: false,
    });
//    // enable Enum
//    registerEnumType(ZzzzzType, {
//        name: "ZzzzzType",
//    });