按月和年分组的日期时间差异天数

Question

我想找到两个日期之间的天数，但按月和年分组。

参考

import calendar
from datetime import datetime, timedelta
from itertools import groupby

start = datetime(2020,12,30) 
end = datetime(2021,12,15)

如果开始年份和结束年份不同，我需要按月和年分组的结果。我怎样才能应用代码来获得答案？

非常感谢mucd

Answer 1

基于其他答案中共享的想法，您创建了一个日期列表，map 将它们分配到您想要的组，然后使用 groupby

进行计数

from datetime import datetime, timedelta
from itertools import groupby

start = datetime(2020,12,30) 
end = datetime(2021,12,15) 

dates = (start + timedelta(days=i) for i in range(1, (end - start).days + 1))
year_months = map(lambda x: (x.year, x.month), dates)

for v, g in groupby(year_months):
    print(v, sum(1 for _ in g))


Output:
(2020, 12) 1
(2021, 1) 31
(2021, 2) 28
(2021, 3) 31
(2021, 4) 30
(2021, 5) 31
(2021, 6) 30
(2021, 7) 31
(2021, 8) 31
(2021, 9) 30
(2021, 10) 31
(2021, 11) 30
(2021, 12) 15

按月和年分组的日期时间差异天数

Datetime number of days difference group by months and years

python

datetime

group-by

date

itertools