如何获得连续的相同输入以中断循环？

Question

我正在尝试制作一个学生学分计算器。当用户连续输入 0 两次时，它必须显示文本：You did have too many study breaks。代码也应该到此结束。我什至不知道要开始解决这个问题，但我已经准备好了其余的代码。

def main():

    months=int(input("Enter the number of months: "))
    total=0

    for i in range(months):
        points=float(input("Enter the number of credits in month {}: ".format(i+1)))
        total += points

    average=total/months
    if average >= 5:
        print(f"You are a full time student and your monthly credit point average is {average:.1f}")
    elif average < 5:
        print(f"Your monthly credit point average {average:.1f} does not classify you as a full time student.")



if __name__ == "__main__":
    main()

所以澄清一下，如果用户连续两次输入 0 点，循环应该中断并显示文本。提前谢谢你。

Answer 1

只需跟踪之前的输入：

prev = -1
for i in range(months):
    points=float(input("Enter the number of credits in month {}: ".format(i+1)))
    if not (prev or points):
        break
    total += points
    prev = points

Answer 2

您可以使用变量来跟踪上次输入的先前值。然后检查这个“prev”变量并在每次迭代时与“current”变量进行比较。在获得新输入之前设置此“prev”值很重要。

如果两者相等，则说明用户连续输入了相同的内容。

示例：

def main():

    months=int(input("Enter the number of months: "))
    total=0
    prev=0
    data = 0

    for i in range(months):
        prev = data
        data = input("Enter the number of credits in month {}: ".format(i+1))
        if ((prev==data) && data == 0): 
            print("You have too many study breaks")
            break

        points=float(data)
        total += points

    average=total/months
    if average >= 5:
        print(f"You are a full time student and your monthly credit point average is {average:.1f}")
    elif average < 5:
        print(f"Your monthly credit point average {average:.1f} does not classify you as a full time student.")



if __name__ == "__main__":
    main()

Answer 3

这里是代码，如果需要的话函数已经在里面了：

def main():
    pointsEnd = 0
    months=int(input("Enter the number of months: "))
    total=0

    for i in range(months):
        points=float(input("Enter the number of credits in month {}: ".format(i+1)))
        if points == 0: #here is the new code
            pointsEnd += 1
            if pointsEnd == 2:
                end = print('You did have too many study breaks')
                return end
                ()
        total += points

    average=total/months
    if average >= 5:
        print(f"You are a full time student and your monthly credit point average is {average:.1f}")
    elif average < 5:
        print(f"Your monthly credit point average {average:.1f} does not classify you as a full time student.")



if __name__ == "__main__":
    main()

Answer 4

您可以创建一个新变量来计算重复项，并添加一个“if 语句”，其中 if 语句以“break”结尾

def main():

    //counter
    duplicates = 0

    months=int(input("Enter the number of months: "))
    total=0

    for i in range(months):
        points=float(input("Enter the number of credits in month {}: ".format(i+1)))

        //Add checks if it is a duplicate, if there are 2 or more duplicate, end 
        //for sentence

        if points == 0:
            duplicates += 1
        else:
            duplicates = 0

       if duplicates >= 2:
            break

        total += points

    average=total/months
    if average >= 5:
        print(f"You are a full time student and your monthly credit point average is {average:.1f}")
    elif average < 5:
        print(f"Your monthly credit point average {average:.1f} does not classify you as a full time student.")



if __name__ == "__main__":
    main()

如何获得连续的相同输入以中断循环？

How do I get consecutive same input to break loop?

python

for-loop

break