以小数位报告金额

Question

我正在制定一项所得税计划，其中的计算基于 - 申报状态和 - 应税收入

所有部分必须小数点后两位。

问题是输出在小数点后显示两个零，而不是预期的数字。

例如：

预期价值> 单笔申请：42806 美元。50

实际价值> 单笔申报：$42806.00

到目前为止，这是我的代码：

// Single Status 
        if (status == 1) {
            
            if (income > 0 && income <= 8350) {
                
                double firstTax = (int)(income * (0.10));
                double totalTax = firstTax;
                
                result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) +  ")";
            }
            
            else if (income >= 8350 && income <= 33950) {
                
                double firstTax = (int)(8350 * (0.10));
                double secondTax = (int)( (income - 8350)  * (0.15));
                double totalTax = firstTax + secondTax;
                
                result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) + ", Part II: $" + String.format(("%.2f"),secondTax) +  ")";
            }
            
            else if (income >= 33950) {
                double firstTax = (int)(8350 * (0.10));
                double secondTax = (int)( (33950 - 8350)  * (0.15));
                double thirdTax = (int)((income - 33950) * (0.25)); 
                
                double totalTax = firstTax + secondTax + thirdTax;
                
                result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) + ", Part II: $" + String.format(("%.2f"),secondTax) + ", Part III: $" + String.format(("%.2f"),thirdTax) + ")";
            }
            
        }

Answer 1

//单身状态如果（状态== 1）{

        if (income > 0 && income <= 8350) {
            
            double firstTax = (int)(income * (0.10));
            double totalTax = firstTax;
            
            result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) +  ")";
        }
        
        else if (income >= 8350 && income <= 33950) {
            
            double firstTax = (int)(8350 * (0.10));
            double secondTax = (int)( (income - 8350)  * (0.15));
            double totalTax = firstTax + secondTax;
            
            result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) + ", Part II: $" + String.format(("%.2f"),secondTax) +  ")";
        }
        
        else if (income >= 33950) {
            double firstTax = (int)(8350 * (0.10));
            double secondTax = (int)( (33950 - 8350)  * (0.15));
            double thirdTax = (int)((income - 33950) * (0.25));
            
            result = "Single Filing: $" + String.format("%.2f",totalTax) + "(Part I: $" + String.format(("%.2f"),firstTax) + ", Part II: $" + String.format(("%.2f"),secondTax) + ", Part III: $" + String.format(("%.2f"),thirdTax) + ")";
        }
        
    }

Answer 2

您正在将它们投射到 int。这将消除任何小数。删除 (int)，它应该有正确的小数。

Answer 3

您正在将类型转换为 int，但您希望结果为 double。从代码中删除“(int)”。您可以这样更改代码，

double firstTax = (int)(income * (0.10)) => double firstTax = (income * (0.10))

以小数位报告金额

report an amount in decimal places

java

database

report

decimalformat

tax