Laravel 添加构造函数调用服务时出现 Livewire 错误 class

Question

我有一段代码要重用。我读过这篇 Laravel cleaner code article and this other Laravel Services Pattern 文章，其中我意识到我可以通过使用服务 classes 在应用程序的多个位置重用代码。

在这种情况下，我在新文件夹 app/Services/MyService.

中创建了一个新 MyService class

namespace App\Services;

class MyService
{
    public function reuse_code($param){
       return void;
    }
}

当我想通过 Livewire class 组件内部的构造函数调用 class 时，问题就来了，如下所示：

<?php

namespace App\Http\Livewire;

use App\Services\MyService;
use Livewire\Component;
use Livewire\WithPagination;

class LivewireTable extends Component
{
    use WithPagination;

    private $myClassService;

    public function __construct(MyService $myService)
    {
        $this->myClassService = $myService;
    }

    public function render()
    {
       $foo = $this->myClassService->reuse_code($param);
       return view('my.view',compact('foo'));
    }
}

显示的错误如下：

Argument 1 passed to App\Http\Livewire\LivewireTable::__construct() must be an instance of App\Services\MyService, string given

（但是，如果我使用一个特征，没有问题。但我担心我的特征会与以前的经验发生冲突）

我该如何解决？我错过了什么？

Answer 1

已解决 就像 @IGP said, reading in the livewire docs 它说：

In Livewire components, you use mount() instead of a class constructor __construct() like you may be used to.

所以，我的工作代码如下：

<?php

namespace App\Http\Livewire;

use App\Services\MyService;
use Livewire\Component;
use Livewire\WithPagination;

class LivewireTable extends Component
{
    use WithPagination;

    private $myClassService;

    public function mount(MyService $myService)
    {
        $this->myClassService = $myService;
    }

    public function render()
    {
       $foo = $this->myClassService->reuse_code($param);
       return view('my.view',compact('foo'));
    }
}

.

Answer 2

Livewire's boot method Runs on every request, immediately after the component is instantiated, but before any other lifecycle methods are called

这是对我有用的解决方案。

Laravel 添加构造函数调用服务时出现 Livewire 错误 class

Laravel Livewire error when I add a constructor to call a service class

laravel

laravel-livewire