无法对 Python 中的非正方形整数进行编码

Question

如何创建一个代码来打印出所有小于 100 且不是任何整数的平方的整数？

例如，3^2=9 不打印，但 30 应该打印。

我已经设法打印出平方值，但不确定如何打印出不是正方形的值。

这是我的代码：

for i in range(1,100):
    square = i**2

    print(square)

Answer 1

您可以将整数的平方存储到数组中。

squares =[]
for i in range(1,100):
    squares.append(i**2)

j = 0
for k in range(1,100):
    if k==squares[j]:
        j=j+1
    elif k>squares[j]:
        print(k)
        j=j+1
    else:
        print(k)

Answer 2

您可以通过多种方式编写此代码。我想你可以在这里使用两个 for 循环来让你更容易。我正在使用评论，以便您作为新手更好地理解。您可以从这两个中选择一个您认为更容易理解的：

list_of_squares = []               #list to store the squares
              
for i in range(1, 11):             #since we know 10's square is 100 and we only need numbers less than that
    square = i ** 2
    list_of_squares.append(square) #'append' keeps adding each number's square to this list
    
for i in range(1, 100):
    if i not in list_of_squares:   #'not in' selects only those numbers that are not in the squares' list
        print(i)

或者

list_of_squares = []

for i in range(1, 100):
    square = i ** 2
    list_of_squares.append(square)
    if square >= 100:              #since we only need numbers less than 100
        break                      #'break' breaks the loop when square reaches a value greater than or equal to 100
        
for i in range(1, 100):
    if i not in list_of_squares:
        print(i)

无法对 Python 中的非正方形整数进行编码

Unable to code for non-squares integers in Python

python

printing

integer

for-loop

python-3.x