Laravel

Question

我在 Laravel-5.8:

中有这个模型

class Employee extends Model
{
    public $timestamps = false;
    protected $table = 'employees';
    protected $primaryKey = 'id';

    protected $fillable = [
                  'id',
                  'first_name',
                  'last_name',
                  'hr_status',      
                  'employee_type_id',
              ];

    public function employeetype()
    {
        return $this->belongsTo('App\Models\Hr\EmployeeType','employee_type_id','id');
    }           
}


class EmployeeType extends Model
{
    public $timestamps = false;
    protected $table = 'employee_types';
    protected $primaryKey = 'id';

    protected $fillable = [
                  'type_name',
                  'is_active',
              ];
}

然后我在员工控制器函数中有这个查询：

 $unsubmitted = Employee::where('hr_status', 0)->get();

如何将 employee_types 中的 is_active = 1 包含到 Employee 的查询中：

$unsubmitted = Employee::where('hr_status', 0)->get();

Answer 1

您正在寻找whereHas方法，查询关系是否存在：

Employee::where('hr_status', 0)
    ->whereHas('employeetype', function ($q) {
        $q->where('is_active', 1);
    })->get();

Laravel 5.8 Docs - Eloquent - Relationships - Querying Relationship Existence whereHas

Laravel - 如何查询Eloquent关系？

Laravel - How to query Eloquent relationship?

php

laravel-5.8