从 XML 的所有路径获取键的值

Question

我有一个xml

<EmployeeDetails>
    <BusinessEntityID>3</BusinessEntityID>
    <StoreDetail>
        <Sale>
            <AnnualSales>800000</AnnualSales>
        </Sale>
        <Sale>
            <AnnualSales>300000</AnnualSales>
        </Sale>
    </StoreDetail>
    <Revenue>
        <StoreDetail>
            <Sale>
                <AnnualSales>800000</AnnualSales>
            </Sale>
            <Sale>
                <AnnualSales>300000</AnnualSales>
            </Sale>
        </StoreDetail>
    </Revenue>
    <Report>
        <Sale>
            <AnnualSales>900000</AnnualSales>
        </Sale>
    </Report>
</EmployeeDetails>

我正在查找节点 <sale> 中 AnnualSales 的所有值。它可以在 EmployeeDetails-->StoreDetail-->Sale 或 EmployeeDetails-->StoreDetail-->Revenue-->Sale 下，也可以在其他树下。是否可以找到所有 sale 而不管路径？

目前我使用下面的代码，我只得到一条路径（2 行）

SELECT 
    X.Y.value('(AnnualSales)[1]', 'VARCHAR(20)') as AnnualSales
FROM test e
CROSS APPLY e.xml_data.nodes('EmployeeDetails/StoreDetail/Sale') as X(Y)

DbFiddle

预期输出：

Answer 1

请尝试以下操作。

由于XML结构不一致，我们不得不在.nodes()方法中使用效率最低的XPath表达式。而且我不确定返回值的正确数据类型。恕我直言，可能是 DECIMAL(x,y).

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, xmldata XML);
INSERT INTO @tbl (xmldata) VALUES
(N'<EmployeeDetails>
    <BusinessEntityID>3</BusinessEntityID>
    <StoreDetail>
        <Sale>
            <AnnualSales>800000</AnnualSales>
        </Sale>
        <Sale>
            <AnnualSales>300000</AnnualSales>
        </Sale>
    </StoreDetail>
    <Revenue>
        <StoreDetail>
            <Sale>
                <AnnualSales>800000</AnnualSales>
            </Sale>
            <Sale>
                <AnnualSales>300000</AnnualSales>
            </Sale>
        </StoreDetail>
    </Revenue>
    <Report>
        <Sale>
            <AnnualSales>900000</AnnualSales>
        </Sale>
    </Report>
</EmployeeDetails>');
-- DDL and sample data population, end

SELECT c.value('(./text())[1]', 'VARCHAR(20)') AS AnnualSales
FROM @tbl CROSS APPLY xmldata.nodes('//AnnualSales') AS t(c);

输出

+-------------+
| AnnualSales |
+-------------+
|      800000 |
|      300000 |
|      800000 |
|      300000 |
|      900000 |
+-------------+

从 XML 的所有路径获取键的值

Get value of key from all path of XML

xml

sql-server

xquery

sql-server-2012