简单代码：如何定义测距变量？（代码错误）

Question

代码输出错误：名称'numAttacks'未定义。如果 numAttacks 将基于用户在 def 难度下的输入，我该如何定义它？

def fightBattle(difficulty):
    if (difficulty == "easy"):
        numAttacks = 10
    elif (difficulty == "hard"):
        numAttacks = 5
difficulty = input("Which difficulty mode you wish to play on?: (Easy/ Hard) ")


def game():
    for i in range (numAttacks):
        print("Village")
game()

Answer 1

函数应 return 值，以便您可以将其分配给变量。

def fightBattle(difficulty):
    if (difficulty == "easy"):
        numAttacks = 10
    elif (difficulty == "hard"):
        numAttacks = 5
    else:
        raise ValueError("Difficulty should be easy or hard")
    return numAttacks

def game():
    print("something")
    difficulty = input("Which difficulty mode you wish to play on?: (Easy/ Hard) ")
    numAttacks = fightBattle(difficulty)
    for i in range (numAttacks):
        print("Village")

game()

简单代码：如何定义测距变量？（代码错误）

SIMPLE CODE: How to define a ranging variable? (Code error)

python

variables

if-statement

function

traceback

简单代码：如何定义测距变量？ （代码错误）

SIMPLE CODE: How to define a ranging variable? (Code error)

python

variables

if-statement

function

traceback

简单代码：如何定义测距变量？（代码错误）