如何使用连接和列表理解连接字典项目列表？

Question

我正在尝试使用列表理解从列表中的所有词典中获取具有所有属性的格式化字符串

results = [{'TTL': '1643410114', 'customer': '1212', 'date': '2021-01-28', 'file': 'file.gz'}]

print("***** SEARCH RESULTS ***** \n".join([ f"{key}: {value}\n" for key, value in obj.items() for obj in results ]))

我得到了 NameError: name 'obj' is not defined，我尝试了一些组合但没有成功，我该如何实现？

Answer 1

您的内联 for 循环顺序错误：

>>> [ "{}: {}\n".format(key, value) for obj in results for key, value in obj.items() ]
['customer: 1212\n', 'date: 2021-01-28\n', 'file: file.gz\n', 'TTL: 1643410114\n']

Answer 2

你需要调换两个for循环的顺序。

results = [{'TTL': '1643410114', 'customer': '1212', 'date': '2021-01-28', 'file': 'file.gz'}]

print("***** SEARCH RESULTS ***** \n".join([ f"{key}: {value}\n" for obj in results for key, value in obj.items()]))

输出

TTL: 1643410114
***** SEARCH RESULTS ***** 
customer: 1212
***** SEARCH RESULTS ***** 
date: 2021-01-28
***** SEARCH RESULTS ***** 
file: file.gz

Answer 3

这是实现它的路径...

print("***** SEARCH RESULTS *****")
print(str([k +' : '+ results[0][k] for k in results[0]]).replace('[','').replace(']','').replace(',','\n').replace("'",""))

Answer 4

results = [{'TTL': '1643410114', 'customer': '1212', 'date': '2021-01-28', 'file': 'file.gz'},
      {'TTL': '1643410115', 'customer': '1312', 'date': '2021-02-27', 'file': 'file2.gz'}
      ]

#print(results)
for obj in results: 
     for key, value in obj.items():
        if (key=='file'):
             print(obj['TTL'],key,value)


output
1643410114 file file.gz
1643410115 file file2.gz

如何使用连接和列表理解连接字典项目列表？

How to concatenate list of dictionaries items using join and list comprehension?

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