为什么应用 xlrd.xldate_as_datetime() 函数没有按预期更新数据帧的子集?

Why applying xlrd.xldate_as_datetime() function does not update subset of dataframe as expected?

我从 excel 文件中提取了一个数据帧,该文件有一个日期时间列,但有一些 excel 日期格式的值,如下所示:

import pandas as pd
import numpy as np
import xlrd

rnd = np.random.randint(0,1000,size=(10, 1))
test = pd.DataFrame(data=rnd,index=range(0,10),columns=['rnd'])
test['Date'] = pd.date_range(start='1/1/1979', periods=len(test), freq='D')
r1 = np.random.randint(0,5)
r2 = np.random.randint(6,10)
test.loc[r1, 'Date'] = 44305
test.loc[r2, 'Date'] = 44287
test

    rnd     Date
0   56  1979-01-01 00:00:00
1   557     1979-01-02 00:00:00
2   851     1979-01-03 00:00:00
3   553     44305
4   258     1979-01-05 00:00:00
5   946     1979-01-06 00:00:00
6   930     1979-01-07 00:00:00
7   805     1979-01-08 00:00:00
8   362     44287
9   705     1979-01-10 00:00:00

当我尝试单独使用 xlrd.xldate_as_datetime 函数转换错误日期时,我得到了一个格式正确的系列:

# Identifying the index of dates in int format
idx_ints = test[test['Date'].map(lambda x: isinstance(x, int))].index

test.loc[idx_ints, 'Date'].map(lambda x: xlrd.xldate_as_datetime(x, 0))

3   2021-04-19
8   2021-04-01
Name: Date, dtype: datetime64[ns]

然而,当我尝试就地应用更改时,我得到一个截然不同的整数:

test.loc[idx_ints,'Date'] = test.loc[idx_ints, 'Date'].map(lambda x: xlrd.xldate_as_datetime(x, 0))

test
  
    rnd     Date
0   56  1979-01-01 00:00:00
1   557     1979-01-02 00:00:00
2   851     1979-01-03 00:00:00
3   553     1618790400000000000
4   258     1979-01-05 00:00:00
5   946     1979-01-06 00:00:00
6   930     1979-01-07 00:00:00
7   805     1979-01-08 00:00:00
8   362     1617235200000000000
9   705     1979-01-10 00:00:00

任何想法,或者可能是我的日期 int 转换问题的替代解决方案,谢谢!

反转我链接的答案的逻辑,这对你的测试 df:

# where you have numeric values, i.e. "excel datetime format":
nums = pd.to_numeric(test['Date'], errors='coerce') # timestamps will give NaN here
# now first convert the excel dates:
test.loc[nums.notna(), 'datetime'] = pd.to_datetime(nums[nums.notna()], unit='d', origin='1899-12-30')
# ...and the other, "parseable" timestamps:
test.loc[nums.isna(), 'datetime'] = pd.to_datetime(test['Date'][nums.isna()])

test
   rnd                 Date   datetime
0  840                44305 2021-04-19
1  298  1979-01-02 00:00:00 1979-01-02
2  981  1979-01-03 00:00:00 1979-01-03
3  806  1979-01-04 00:00:00 1979-01-04
4  629  1979-01-05 00:00:00 1979-01-05
5  540  1979-01-06 00:00:00 1979-01-06
6  499  1979-01-07 00:00:00 1979-01-07
7  155  1979-01-08 00:00:00 1979-01-08
8  208                44287 2021-04-01
9  737  1979-01-10 00:00:00 1979-01-10

如果您的输入已经有日期时间对象而不是时间戳字符串,您可以跳过转换并将值转移到我认为的新列。