Why this code in python gives this error? TypeError: object of type 'int' has no len() but i'm calling it on a list
Why this code in python gives this error? TypeError: object of type 'int' has no len() but i'm calling it on a list
此代码抛出以下错误:
while len(digits) > 1:
TypeError: object of type 'int' has no len()
但我的可变数字是一个列表,对吗?我想一定有我不明白的列表理解
def per(n):
if len(str(n)) == 1:
return n
else:
digits = [int(i) for i in str(n)]
count = 1
while len(digits) > 1: # TypeError:object of type 'int' has no len()
result = 1
for j in digits:
result *= j
digits = result
count += 1
return count
print(per(716235))
def per(n):
if len(str(n)) == 1:
return n
else:
digits = [int(i) for i in str(n)]
count = 1
while len(digits) > 1:
result = 1
for j in digits:
result *= j
digits = result # <-------- Right here you are setting digits
# <-------- as result which is an integer
count += 1
return count
print(per(716235))
此代码抛出以下错误:
while len(digits) > 1:
TypeError: object of type 'int' has no len()
但我的可变数字是一个列表,对吗?我想一定有我不明白的列表理解
def per(n):
if len(str(n)) == 1:
return n
else:
digits = [int(i) for i in str(n)]
count = 1
while len(digits) > 1: # TypeError:object of type 'int' has no len()
result = 1
for j in digits:
result *= j
digits = result
count += 1
return count
print(per(716235))
def per(n):
if len(str(n)) == 1:
return n
else:
digits = [int(i) for i in str(n)]
count = 1
while len(digits) > 1:
result = 1
for j in digits:
result *= j
digits = result # <-------- Right here you are setting digits
# <-------- as result which is an integer
count += 1
return count
print(per(716235))