是的验证，一个字符串上有 2 个正则表达式

Question

我有这个架构可以根据几个要求验证 2 个密码字段：

“密码必须包含 8 个或更多字符，至少一个大写字母和一个数字。”
"密码不能包含 _ @ . - 以外的特殊字符"

现在我在一个字符串中显示两个验证错误，但我需要为这些条件显示 2 个单独的错误。

问题是，我如何创建 2 个正则表达式，它们在验证时不会相互冲突，并且会向我显示必要的错误？

  const format = /[a-z`!#$%^&*()+=\[\]{};':"\|,<>\/?~]/;
  const passwordFormat = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d_@.-]{8,}$/;

  return yup.object().shape({
    password: yup
      .string()
      .required("Password is required")
// validates the password
      .matches(passwordFormat, "Password must have 8 or more characters, at least one uppercase letter, and one number.")
//checks if there are special characters
      .test('special-chars', "Password cannot contain special characters other than _ @ . -", function(value) {
        return format.test(value);
      })
      .strict(true)
  });

Answer 1

你可以试试这两个：

^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[\S]{8,}$ - "Password must have 8 or more characters, at least one uppercase letter, and one number"

^[-@\.\w]*$ - "Password cannot contain special characters other than _ @ . -"

是的验证，一个字符串上有 2 个正则表达式

Yup validation, 2 regex on one string

regex

string

validation

reactjs

yup