循环字典列表并比较其他列表中的任何匹配值

Question

我有一个字典列表，我正在尝试循环并需要检查 rulenames 中的 'pmdruleid' 是否与 activeclientrulelist 中的任何 'pmdruleid' 匹配。我正在使用下面的代码并且每次都得到 None 。下面的代码检查循环中相应的索引值，而不是检查列表中的任何匹配值：

activeclientrulelist = [{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10016, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid':111, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 111, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10020, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

rulenames = [{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
             {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

if len(activeclientrulelist) > 0:
  for rule in rulenames:
     matching_active_client_rule_items = [y for y in activeclientrulelist if y['pmdruleid'] == rule['pmdruleid']

预期输出

[{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
 {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

Answer 1

如果你想找到 2 个字典列表之间的交集，你可以这样做：

res = [x for x in activeclientrulelist if x in rulenames]

而 res 将是：

[{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

如果你只想考虑 pmdruleid 键你可以做，不需要在列表理解之外循环 rulenames 否则你会覆盖结果：

[x for x in activeclientrulelist for y in rulenames if x['pmdruleid'] == y['pmdruleid']]

Answer 2

看来问题是列表每次都会刷新，所以我改成如下：

matching_active_client_rule_items=[]
if len(activeclientrulelist) > 0:
  for rule in rulenames:
     matching_active_client_rule_items.extend( [y for y in activeclientrulelist if y['pmdruleid'] == rule['pmdruleid']])



print(matching_active_client_rule_items)

我在上面定义了一个空列表，并用正确的项目扩展了列表。

Answer 3

您当前的代码有几个问题：

matching_active_client_rule_items = [y for y in activeclientrulelist if y['pmdruleid'] == rule['pmdruleid'] 行末尾缺少 ]。
使用此行：matching_active_client_rule_items = [y for y in activeclientrulelist if y['pmdruleid'] == rule['pmdruleid']，您将仅使用 rulenames 中最后一项的输出覆盖列表对象。

您需要创建一个列表并对其进行扩展以修复代码：

matching_active_client_rule_items = []
if len(activeclientrulelist) > 0:
  for rule in rulenames:
     matching_active_client_rule_items.extend([y for y in activeclientrulelist if y['pmdruleid'] == rule['pmdruleid']])

虽然这可行，但您应该使用如下列表理解方法来获取两个列表的交集：

matching_active_client_rule_items = [x for x in activeclientrulelist for y in rulenames if x['pmdruleid'] == y['pmdruleid']]

Answer 4

尝试以下操作：

activeclientrulelist = [{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10016, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid':111, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 111, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
                        {'pmdruleid': 10020, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

rulenames = [{'pmdruleid': 112, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}, 
             {'pmdruleid': 10160, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1},
             {'pmdruleid': 101, 'createdby': 'Ad hoc Script - PHARMMD\Jake.Woods', 'updatedby': None, 'transferstatuscode': 1}]

result = [check for check in rulenames for rule in activeclientrulelist if rule['pmdruleid']==check['pmdruleid']]
print(result)

在这种情况下， rulenames: 'pmdruleid': 101 不属于 activeclientrulelist 中的词典，因此省略！

循环字典列表并比较其他列表中的任何匹配值

Looping list of dictionaries and compare any matched values in other list

python

list-comprehension