如何将今天的日期解析为参数

Question

我想用今天的日期创建一个参数，以便将其添加到 sql 脚本的查询中。我尝试了以下：

${var:id_date} =  from_timestamp(date_trunc('second', now()),'yyyyMMdd');

但是我遇到了以下问题。

ParseException: Syntax error in line 1:undefined: ${var:id_date} = select from... ^ Encountered: IDENTIFIER Expected: ALTER, COMMENT, COMPUTE, COPY, CREATE, DELETE, DESCRIBE, DROP, EXPLAIN, GRANT, INSERT, INVALIDATE, LOAD, REFRESH, REVOKE, SELECT, SET, SHOW, TRUNCATE, UPDATE, UPSERT, USE, VALUES, WITH CAUSED BY: Exception: Syntax error

Answer 1

设置变量时使用set var:id_date=...;

set var:id_date=from_timestamp(date_trunc('second', now()),'yyyyMMdd');

    select * from mytable where id_date=${var:id_date};

如何将今天的日期解析为参数

How to parse today's date into a parameter

sql

impala