使 1 个随机图层在每个组中可见的脚本 [Photoshop cc2018]

Script to make 1 random layer visible within each group [Photoshop cc2018]

我正在尝试制作一个脚本,该脚本会随机 select 并在 Photoshop 上显示来自所有组的单个图层并将结果导出为 png。

我在这里找到了这个似乎有效的脚本:

function Visible() {
  var Grps = app.activeDocument.layerSets; // loops through all groups
  for(var i = 0; i < Grps.length; i++){
    var tmp = app.activeDocument.layerSets[i].layers.length;
    app.activeDocument.layerSets[i].visible=true;
    var groupChildArr = app.activeDocument.layerSets[i].layers;
    var randLays = Math.floor(Math.random() * tmp);
    groupChildArr[randLays].visible = true;
    Save();
  }
  Revert();
}

function Save() {
  var outFolder = app.activeDocument; // psd name
  var outPath = outFolder.path;
  var fName = "PNG";   // define folder name
  var f = new Folder(outPath + "/" + fName);
  if ( ! f.exists ) {
    f.create()
  }
  var saveFile = new File(outPath + "/" + fName +"/" + "Pattern_" +  num + ".png");
  pngSaveOptions = new PNGSaveOptions();
  pngSaveOptions.interlaced = false;
  app.activeDocument.saveAs(saveFile, pngSaveOptions, true, Extension.LOWERCASE);
}

function Revert(){
  var idslct = charIDToTypeID( "slct" );
  var desc300 = new ActionDescriptor();
  var idnull = charIDToTypeID( "null" );
  var ref163 = new ActionReference();
  var idSnpS = charIDToTypeID( "SnpS" );
  ref163.putName( idSnpS, "test.psd" );
  desc300.putReference( idnull, ref163 );
  executeAction( idslct, desc300, DialogModes.NO );
}

var count = prompt("How many patterns you want","");
for (var x=0 ; x<count;x++){
  var num = x+1;
  Visible();
}
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除了它给我一个错误 8800:发生一般 Photoshop 错误。此功能可能在此版本的 Photoshop 中不可用。 线路:36 -> executeAction( idslct, desc300, DialogModes.NO );

我可以做些什么来让它工作,因为这将极大地帮助加快我的工作进程。 谢谢。

没有看到你的 PSD 是什么样子,很难说。但是,我认为代码在恢复功能上失败了。

试试这个:

function Revert()
{
  // =======================================================
  var idRvrt = charIDToTypeID( "Rvrt" );
  executeAction( idRvrt, undefined, DialogModes.NO );
}