Google+ 通过 Javascript 和 PHP 登录

Question

你能告诉我，我如何通过Google+ Javascript/Php api 获取用户数据（姓名，电子邮件）？我根据这个 tutorial，它描述了如何通过 Javascript 获得 authResult['code']。

没关系，我有。我通过 Ajax 将它发送到服务器，但我不知道如何通过 PHP 获取用户数据，如姓名和电子邮件，但没有任何重定向。这是代码示例 Javascript:

function googleStart()
{
    console.log('googleStart');
    gapi.load('auth2', function()
    {
        auth2 = gapi.auth2.init({
            client_id: '811214467813-v3fmui5dfghte5m0kmohsf6dl11ori3tg.apps.googleusercontent.com',
            // Scopes to request in addition to 'profile' and 'email'
            fetch_basic_profile: false,
            scope: 'profile email'
        });
    });
}

function googleSignIn(authResult)
{
    console.log(authResult);

    if (authResult['code']) {

        console.log(authResult);

        // Hide the sign-in button now that the user is authorized, for example:
        $('#signinButton').attr('style', 'display: none');

        // Send the code to the server
        $.ajax({
            type: 'POST',
            url : "{link :Signgoogle:in}",
            accepts : 'json',
            // Spýtať sa na DJPW čo to tu je zakomentované
            //contentType: 'application/octet-stream; charset=utf-8',
            //processData: false,
            data : {
                'code' : authResult['code'],
                'id_token' : authResult.getAuthResponse().id_token
            },
...

PHP:

public function actionIn()
{
    $code = $_POST['code'];

    $client = new \Google_Client();
    $client->setClientId(self::APP_ID);
    $client->setClientSecret(self::APP_SECRET);
    $client->setRedirectUri(self::REDIRECT_URI);

    $client->authenticate($code);
    $access_token = $client->getAccessToken();
    $client->setAccessToken($access_token);

    $client->getAuth();


    $data = $access_token;

    if($data)
    {
        $this->sendJson(array($data));
    }
    else
    {
        $data = array('error' => '$client->verifyIdToken($id) skočil chybou.');
        $this->sendJson($data);
    }

}
....

PHP 检索 access_token 但没有用户数据。当然，这是一个 ajax 调用，所以我不能像 Google 在每个页面上描述的那样进行任何重定向。你能帮我吗我找不到任何解决办法。

非常感谢。

Answer 1

一旦您拥有用户的经过身份验证的客户端，您将希望向 Google+ people.get API method.

发出请求

$client = new Google_Client();
$client->setClientId(CLIENT_ID);
$client->setClientSecret(CLIENT_SECRET);
$client->setRedirectUri(REDIRECT_URI);
$client->setAccessToken($access_token);
$plus = new Google_Service_Plus($client);
$me = $plus->people->get('me');
print "ID: {$me['id']}\n";
print "Display Name: {$me['displayName']}\n";
print "Image Url: {$me['image']['url']}\n";
print "Url: {$me['url']}\n";

对于他们的 email，您将必须遍历 $me['emails'] 数组并找到 type=account 的值。

Answer 2

如果您不使用 google 客户端库，您可以使用此 google api 要获取客户端详细信息，您只需将令牌传递给此 api https://www.googleapis.com/oauth2/v3/tokeninfo?id_token= < your_token >

$response = file_get_contents ( 'https://www.googleapis.com/oauth2/v3/tokeninfo?id_token=' . $_REQUEST['token'] );

$response = json_decode ( $response );

echo "<pre>";
print_r ( $response );
echo "</pre>";

这将对用户进行身份验证并将return对象

stdClass Object
(
    [iss] => accounts.google.com
    [at_hash] => hE0R********nxg
    [aud] => 79*********************p.apps.googleusercontent.com
    [sub] => 1028*****2
    [email_verified] => true
    [azp] => 7945823****p.apps.googleusercontent.com
    [email] => bik***@gmail.com
    [iat] => 14***7
    [exp] => 1***07
    [name] => Bik****M
    [picture] => https://lh6.googleusercontent.com/-W8cA***/photo.jpg
    [given_name] => Bike***
    [family_name] => M
    [locale] => en
    [alg] => RS256
    [kid] => 70f6c4267*******cb
)

在此处创建示例：http://wiki.workassis.com/implementing-google-sign-in-for-websites

Google+ 通过 Javascript 和 PHP 登录

Google+ login via Javascript and PHP

php

google-plus

google-oauth

google-signin