年份日期差异
DATE DIFF IN YEARS
如何以 'YYYY-MM-DD' 格式查找日期差异。
我正在使用以下两个查询:
SELECT TRUNC(TO_NUMBER(SYSDATE - TO_DATE('1994-08-13')) / 365.25) AS AGE FROM DUAL;
ORA-01861: literal does not match format string
SELECT (TO_DATE(SYSDATE, 'YYYY-MM-DD') - TO_NUMBER('1994-08-13', 'YYYY-MM-DD')) FROM DUAL;
O/P-: -727738
期望o/p:26
只需从另一个日期中减去一个日期即可:
sysdate - date '1994-08-13'
或者
sysdate - to_date('1994-08-13', 'yyyy-mm-dd')
returns两个日期之间的天数。
因此将您的第一个查询重写为:
select (sysdate - date '1994-08-13') / 365.25 as age
from dual
因此,从这些日期中提取 年并减去 年:
SQL> select extract (year from sysdate) - extract(year from date '1994-08-13') diff
2 from dual;
DIFF
----------
27
SQL>
因为,
SQL> select 2021 - 1994 diff from dual;
DIFF
----------
27
SQL>
我建议使用“months_between”函数,因为它考虑了闰年(months_between 需要 2 个日期作为参数):
select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual;
26,4729751904122
当然,如果需要截断:
select trunc(months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12) from dual;
26
如何以 'YYYY-MM-DD' 格式查找日期差异。
我正在使用以下两个查询:
SELECT TRUNC(TO_NUMBER(SYSDATE - TO_DATE('1994-08-13')) / 365.25) AS AGE FROM DUAL;
ORA-01861: literal does not match format string
SELECT (TO_DATE(SYSDATE, 'YYYY-MM-DD') - TO_NUMBER('1994-08-13', 'YYYY-MM-DD')) FROM DUAL;
O/P-: -727738
期望o/p:26
只需从另一个日期中减去一个日期即可:
sysdate - date '1994-08-13'
或者
sysdate - to_date('1994-08-13', 'yyyy-mm-dd')
returns两个日期之间的天数。
因此将您的第一个查询重写为:
select (sysdate - date '1994-08-13') / 365.25 as age
from dual
因此,从这些日期中提取 年并减去 年:
SQL> select extract (year from sysdate) - extract(year from date '1994-08-13') diff
2 from dual;
DIFF
----------
27
SQL>
因为,
SQL> select 2021 - 1994 diff from dual;
DIFF
----------
27
SQL>
我建议使用“months_between”函数,因为它考虑了闰年(months_between 需要 2 个日期作为参数):
select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual;
26,4729751904122
当然,如果需要截断:
select trunc(months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12) from dual;
26