字梯c程序

Question

我写了字梯的C代码。它正在验证给定的测试用例。但是对于 1 个测试用例，它的输出是错误的，我不知道应该在哪里进行更改。

问题

There is a class of word puzzles where you are given two words, such as BEAK and MAKE, and have to get from one to another by changing one letter at a time. Solving such puzzles requires a good vocabulary and some lateral thinking, but checking the solution once you have one is merely tedious and suitable for a computer to do. Note that even correct solutions are not guaranteed to be minimal.

A solution is correct if, for each pair of adjacent words in the ladder, the following apply:

they are the same length

there is exactly one letter changed.

Write a program that will check proposed solutions.

Input Format:

Input will be a solution i.e it consists of a series of words, one per line, terminated by a line containing a single #. A word is a sequence --- between three and twenty uppercase letters.

Output Format:

Output the word ‘Correct’ or ‘Incorrect’ as appropriate.

Sample Input 1:

BARK
BARE
#

Sample Output 1:

Correct

Sample Input 2:

MAKE
BAKE
BONK
BONE
BANE
#

Sample Output 2:

Incorrect

我的代码

#include<stdio.h>
#include<string.h>
int main()
{
  int i,count;
  char a[100],b[100],c[100];
  int flag=1;
  scanf("%s",a);
  do
  {
 scanf("%s",b);
    if(b[0]=='#')
   break;
    if(strlen(a)==strlen(b))
    {  i=0,count=0;
     while(a[i]!='[=10=]')
     {

       if(a[i]!=b[i])
         count++;
         if(count==2)
         {
         flag=0;
         }

       i++;
     }
   }
    else
    {
      flag=0;
    }
    scanf("%s",a);
    if(a[0]=='#')
      break;
   //  scanf("%s",c);
   strcpy(c,a);
   strcpy(a,b);
    strcpy(b,c);

   }
   while(a[0]!='#');
  if(flag==1)
   printf("Correct");
  else
    printf("Incorrect");
   return 0;
   }

此输入的程序输出不正确

code -> cade -> cate -> date -> data

Answer 1

您读字次数过多。我的意思是，你读的比你比较的多。

看看这个：

第一个 scanf()（进入 a）不算数。曾经有东西可以比较
秒scanf()（进入b）循环
循环中a和b的比较
循环中的第三个 scanf()（进入 a）！！
在 2 处重复。

循环内应该只有 1 个 scanf() 和 1 个比较。

_{你的缩进也很疼}

字梯c程序

c program for word ladder

c

word