Python

Question

我有一个函数，当我使用 list.append 时似乎正在保存变量。当我打印每个增量时，列表会发生变化。当我打印列表的完整列表时，每个元素都是相同的（变量列表的最后一个实例）。如何强制主列表保存以前的实例？

base 函数只是将列表从 base-10 转换为新的 base（在我的示例中为 base-4）

list1 = ["v", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n"]

def combo(object_list, spots):
    pool = len(object_list)
    total = pool**spots
    permlist = list()
    wordlist = list()
    z = []
    for i in range(total):  
        print("top", wordlist) 
        wordlist.clear()
        z = base(i,pool,spots) 
        for q in z:  
            j=-1
            for a in object_list:
                j+=1
                if int(q) == int(j):
                    wordlist.append(a)
        permlist.append(wordlist)
    return permlist


def base(number, base, digits):
    remainder = []
    result = [0,0]
    while number >0:
        dividend = number // int(base)
        remainder.append(str(number % int(base)))
        number = dividend
        result = list(reversed(remainder))
    while len(result) < digits:
        result.insert(0,0)
    return result

print (combo(list1,4))

Answer 1

或者，

wordlist = []

而不是

wordlist.clear()

Python - 保存到列表时丢失变量实例

Python - Losing instances of variable when saving into list

list

instance