如何只获取文本 BeautifulSoup

Question

我是第一次发贴。我正在制作一个程序来告诉天气，请求和 BeautifulSoup 格式化正确的信息是错误的。我有

import requests
from bs4 import BeautifulSoup

url = 'https://weather.com/en-IN/weather/today/l/91ae3bca47e7dbeb23a6f4b10cb656d234e65f12a1e9b4dc80a0e02e5baa838c'


def getdata(url):
    r = requests.get(url)
    return r.text


htmldata = getdata(
    "https://weather.com/en-IN/weather/today/l/91ae3bca47e7dbeb23a6f4b10cb656d234e65f12a1e9b4dc80a0e02e5baa838c")

soup = BeautifulSoup(htmldata, 'html.parser')

precip = soup.find('div', id='WxuTodayWeatherCard-main-486ce56c-74e0-4152-bd76-7aea8e98520a')

currentPrecip = precip.find('li')

for j in currentPrecip:
    showPrecip = currentPrecip.get_text()

result = f"Current Temp: {showPrecip}"

print(result)

程序正在输出Current Temp: Morning-5°Snow--，我希望它输出Current Temp: -5°C, Sky Snow

感谢任何帮助并提前致谢

Answer 1

您的问题不是很清楚，您进行预测并期望当前数据。这可能应该改进。

当前：

live = soup.select_one('div.styles--card--3aeCQ a')
print(f"Current Temp: {live.find('span').get_text()}, Sky: {live.find('svg').get_text()}")

预报（上午）：

morning = soup.select_one('section[data-testid="TodayWeatherModule"] ul>li')
print(f"Current Temp: {morning.div.span.get_text()}, Sky: {morning.find('title').get_text()}")

例子

import requests
from bs4 import BeautifulSoup

url = 'https://weather.com/en-IN/weather/today/l/91ae3bca47e7dbeb23a6f4b10cb656d234e65f12a1e9b4dc80a0e02e5baa838c'
soup = BeautifulSoup(requests.get(url).text, 'html.parser')

live = soup.select_one('div.styles--card--3aeCQ a')
print(f"Current Temp: {live.find('span').get_text()}, Sky: {live.find('svg').get_text()}")

morning = soup.select_one('section[data-testid="TodayWeatherModule"] ul>li')
print(f"Current Temp: {morning.div.span.get_text()}, Sky: {morning.find('title').get_text()}")

输出

Current Temp: -2°, Sky: Snow
Current Temp: -5°, Sky: Snow

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