Pydantic - 如何子类化内置类型

Pydantic - How to subclass a builtin type

我正在尝试制作一个 timedelta 的子类,它希望接收毫秒而不是秒,但它目前无法正常工作。

我是否违背了规律? Pydantic 是否有一种“正确”的方法来实现这一目标?或者我是否需要以某种方式告诉 Pydantic MillisecondTimedelta 只是一个 timedelta..

from datetime import timedelta

from pydantic import BaseModel


class MillisecondTimedelta(timedelta):
    @classmethod
    def __get_validators__(cls):
        # timedelta expects seconds
        yield lambda v: v / 1000
        yield cls


class MyModel(BaseModel):
    td: MillisecondTimedelta

data = {
    "td": 7598040,
}

print(MyModel(**data))

结果:

Traceback (most recent call last):
  File "main.py", line 14, in <module>
    class MyModel(BaseModel):
  File "pydantic/main.py", line 262, in pydantic.main.ModelMetaclass.__new__
  File "pydantic/fields.py", line 315, in pydantic.fields.ModelField.infer
  File "pydantic/fields.py", line 284, in pydantic.fields.ModelField.__init__
  File "pydantic/fields.py", line 362, in pydantic.fields.ModelField.prepare
  File "pydantic/fields.py", line 541, in pydantic.fields.ModelField.populate_validators
  File "pydantic/class_validators.py", line 255, in pydantic.class_validators.prep_validators
  File "pydantic/class_validators.py", line 238, in pydantic.class_validators.make_generic_validator
  File "/usr/lib/python3.8/inspect.py", line 3105, in signature
    return Signature.from_callable(obj, follow_wrapped=follow_wrapped)
  File "/usr/lib/python3.8/inspect.py", line 2854, in from_callable
    return _signature_from_callable(obj, sigcls=cls,
  File "/usr/lib/python3.8/inspect.py", line 2384, in _signature_from_callable
    raise ValueError(
ValueError: no signature found for builtin type <class '__main__.MillisecondTimedelta'>

如图on the doc page of __get_validators__()所示,您需要产生一个或多个验证器。

修改后的class报告如下;问题是 Pydantic 理解(对于 timedelta 字段)int 和浮点数秒 (source).

class MillisecondTimedelta(timedelta):
    @classmethod
    def __get_validators__(cls):
        yield cls.validate

    @classmethod
    def validate(cls, v):
        if any(isinstance(v, t) for t in (int, float)):
            return cls(milliseconds=v)

现在一切都应该正常工作了。

>>> data = {"td": 1000}
>>> print(MyModel(**data))
td=MillisecondTimedelta(seconds=1)

编辑:没有自定义 class 和验证器,可以使用函数来编辑分配给 class 构造函数的值;需要修饰这个函数,as seen here

class MyModel(BaseModel):
    td: timedelta

    @validator('td')
    def convert_to_ms(cls, v):
        return v / 1000

此解决方案也有效:

>>> data = {"td": 3000}
>>> print(MyModel(**data))
td=datetime.timedelta(seconds=3)

啊哈,原来我需要改变两件事。

  1. 实际上 return 来自验证器的 timedelta,我正在 returning cls 这是我的自定义子类。

  2. 不要继承 timedelta

from datetime import timedelta

from pydantic import BaseModel


class MillisecondTimedelta:

    @classmethod
    def __get_validators__(cls):
        yield lambda v: timedelta(milliseconds=v)


class MyModel(BaseModel):
    td: MillisecondTimedelta


data = {
    "td": 7598040,
}

print(repr(MyModel(**data)))
MyModel(td=datetime.timedelta(seconds=7598, microseconds=40000))