如何在 sequelize 的子子模型中添加条件,这会影响 findAndCountAll 中的父模型?
How do I add conditions in sub-sub child models in sequelize which should impact my parent Model in findAndCountAll?
在 sequelize 中,我想在 sub-sub 子模型中的 findAndCountAll 调用中添加一个条件。如果条件为假,它应该影响父模型并且 findAndCountAll 应该 return 数组长度为 0。目前,只有子子模型的数组长度为 0,其余的父模型正在 returned .
我在分享的代码中添加了更多细节。
我的代码是这样的:
const { limit, offset } = dbHelpers.GetPagination(
req.query.limit,
req.query.offset
);
const results = await models.ModelA.findAndCountAll({
where: condition,
distinct: true,
limit,
offset,
order: [["id", "DESC"]],
include: [
{
model: models.ModelB,
as: "ModelB",
include: [
{
model: models.ModelC,
separate: true,
},
{
model: models.ModelD,
separate: true,
include: [
{
model: models.ModelE,
separate: true,
{
model: models.ModelF,
where: "I want to add my condition here which should impact the whole query if not found just like the condition I have added in ModelG",
separate: true,
},
],
},
],
},
],
},
{
model: models.ModelG,
where: "I have added a condition here and if nothing is found, my parent query returns nothing which is exactly what I want.",
include: [
{
model: models.ModelH,
as: "ModelH",
},
],
},
],
});
好的,所以我找到了解决方案,但添加了一个带有连接的原始查询,在其中我在需要的地方添加了我需要的条件,并获取了主模型的 ID。然后我使用 sequelize 在 where 子句中添加这些 id 来获取数据。我的代码现在看起来像这样。
const { limit, offset } = dbHelpers.GetPagination(
req.query.limit,
req.query.offset
);
let querySting = "(SELECT count(DISTINCT p.id) FROM ModelA p " +
"JOIN ModelB cp ON cp.pId = p.id " +
"JOIN ModelC cs ON cs.cpId = cp.id " +
"JOIN ModelD ms ON ms.csId = cs.id " +
"LEFT JOIN ModelE sa ON sa.msId = ms.id " +
"LEFT JOIN ModelF pp ON pp.msId = ms.id " +
"LEFT JOIN ModelG sta ON sta.ppId = pp.id " +
"LEFT JOIN ModelH ol ON ol.cdId = cd.id " +
"WHERE " //you can add your conditions here
+ " ORDER BY p.id desc LIMIT " + offset + ", " + limit + ")"
const rawQuery = await models.sequelize.query(querySting,
{ type: QueryTypes.SELECT })
const Ids = rawQuery.map(result => result.id)
const results = await models.ModelA.findAndCountAll({
where: {
id: Ids
},
include: [
{
model: models.ModelB,
as: "ModelB",
include: [
{
model: models.ModelC,
separate: true,
},
{
model: models.ModelD,
separate: true,
include: [
{
model: models.ModelE,
separate: true,
{
model: models.ModelF,
separate: true,
},
],
},
],
},
],
},
{
model: models.ModelG,
include: [
{
model: models.ModelH,
as: "ModelH",
},
],
},
],
});
在 sequelize 中,我想在 sub-sub 子模型中的 findAndCountAll 调用中添加一个条件。如果条件为假,它应该影响父模型并且 findAndCountAll 应该 return 数组长度为 0。目前,只有子子模型的数组长度为 0,其余的父模型正在 returned .
我在分享的代码中添加了更多细节。 我的代码是这样的:
const { limit, offset } = dbHelpers.GetPagination(
req.query.limit,
req.query.offset
);
const results = await models.ModelA.findAndCountAll({
where: condition,
distinct: true,
limit,
offset,
order: [["id", "DESC"]],
include: [
{
model: models.ModelB,
as: "ModelB",
include: [
{
model: models.ModelC,
separate: true,
},
{
model: models.ModelD,
separate: true,
include: [
{
model: models.ModelE,
separate: true,
{
model: models.ModelF,
where: "I want to add my condition here which should impact the whole query if not found just like the condition I have added in ModelG",
separate: true,
},
],
},
],
},
],
},
{
model: models.ModelG,
where: "I have added a condition here and if nothing is found, my parent query returns nothing which is exactly what I want.",
include: [
{
model: models.ModelH,
as: "ModelH",
},
],
},
],
});
好的,所以我找到了解决方案,但添加了一个带有连接的原始查询,在其中我在需要的地方添加了我需要的条件,并获取了主模型的 ID。然后我使用 sequelize 在 where 子句中添加这些 id 来获取数据。我的代码现在看起来像这样。
const { limit, offset } = dbHelpers.GetPagination(
req.query.limit,
req.query.offset
);
let querySting = "(SELECT count(DISTINCT p.id) FROM ModelA p " +
"JOIN ModelB cp ON cp.pId = p.id " +
"JOIN ModelC cs ON cs.cpId = cp.id " +
"JOIN ModelD ms ON ms.csId = cs.id " +
"LEFT JOIN ModelE sa ON sa.msId = ms.id " +
"LEFT JOIN ModelF pp ON pp.msId = ms.id " +
"LEFT JOIN ModelG sta ON sta.ppId = pp.id " +
"LEFT JOIN ModelH ol ON ol.cdId = cd.id " +
"WHERE " //you can add your conditions here
+ " ORDER BY p.id desc LIMIT " + offset + ", " + limit + ")"
const rawQuery = await models.sequelize.query(querySting,
{ type: QueryTypes.SELECT })
const Ids = rawQuery.map(result => result.id)
const results = await models.ModelA.findAndCountAll({
where: {
id: Ids
},
include: [
{
model: models.ModelB,
as: "ModelB",
include: [
{
model: models.ModelC,
separate: true,
},
{
model: models.ModelD,
separate: true,
include: [
{
model: models.ModelE,
separate: true,
{
model: models.ModelF,
separate: true,
},
],
},
],
},
],
},
{
model: models.ModelG,
include: [
{
model: models.ModelH,
as: "ModelH",
},
],
},
],
});