当达到某个索引值时，如何停止将数字添加到列表的 while 循环？

Question

我做了一个 while 循环，当它里面的东西的数量达到 'count' 变量时需要停止，但我不太确定如何去做。这是上下文的完整代码，但我遇到麻烦的部分在最后。此外，当用户输入错误时，代码会出错，这可能是我尝试几次后可以自己修复的问题，但我不确定如何修复。无论如何，这里的主要问题是 while 循环。提前感谢您的帮助。

count = int(input("How many numbers should the sequence have? "))
question = input("AP or GP? ")

# Asking the user for input on how many numbers the sequence will have
if question == "AP":
    APdiff = int(input("Insert the common difference for the AP: "))
    while type(APdiff) != int:
        print("Insert a valid input.")
        APdiff = int(input("Insert the common difference for the AP: "))
elif question == "GP":
    GPdiff = int(input("Insert the common ratio for the GP: "))
    while type(GPdiff) != int:
        print("Insert a valid input.")
        GPdiff = int(input("Insert the common ratio for the GP: "))
while question != "AP" and question != "GP":
    print("Please enter a valid input.")
    question = input("AP or GP? ")


def sequence_generator():


    #Setting up the sequences
    sequence = []
    number = 1

    #Defining the AP
    if question == "AP":
        while number in range(1, 99999999999999999999999999999999):
            sequence.append(number)
            number += APdiff
            if sequence.index() == count:
                break
    #Defining the GP
    elif question == "GP":
        while number in range(1, 99999999999999999999999999999999):
            sequence.append(number)
            number *= GPdiff
            if sequence.index() == count:
                break
    return sequence



print(sequence_generator())

Answer 1

您可以使用 while len(sequence)<count。你最终会得到这样的东西

count = int(input("How many numbers should the sequence have? "))
question = input("AP or GP? ")

# Asking the user for input on how many numbers the sequence will have
if question == "AP":
    APdiff = int(input("Insert the common difference for the AP: "))
    while type(APdiff) != int:
        print("Insert a valid input.")
        APdiff = int(input("Insert the common difference for the AP: "))
elif question == "GP":
    GPdiff = int(input("Insert the common ratio for the GP: "))
    while type(GPdiff) != int:
        print("Insert a valid input.")
        GPdiff = int(input("Insert the common ratio for the GP: "))
while question != "AP" and question != "GP":
    print("Please enter a valid input.")
    question = input("AP or GP? ")


def sequence_generator():


    #Setting up the sequences
    sequence = []
    number = 1

    #Defining the AP
    if question == "AP":
        while len(sequence)<count:
            sequence.append(number)
            number += APdiff
    #Defining the GP
    elif question == "GP":
        while len(sequence)<count:
            sequence.append(number)
            number *= GPdiff
    return sequence



print(sequence_generator())

Answer 2

While 循环在满足条件语句之前不会中断。例如：

x = 0
while (x < 5):
  print(x)
  x += 1
print('All done')

会输出

0
1
2
3
4
All done

程序会执行代码块直到条件满足，然后跳出循环，不会打印5。

要在 while 循环中断时执行操作，只需将代码放在 while 块之后。

当达到某个索引值时，如何停止将数字添加到列表的 while 循环？

How do I stop a while loop that adds numbers to a list when a certain index value is reached?

python

loops

list

sequence

while-loop