在 C 中使用转义序列 \r 后，如何将光标移至行尾（不影响行的内容）？

Question

我想知道如何将光标移动到行尾而不覆盖该行的内容：

例如：

#include <stdio.h>

int main(void)
{
    printf("This is a test line\r");
    printf("###"); // Cursor moves to start of the line and over writes the content
    printf("I want to print this at the end of the line"); // I want to take the cursor to the end of the line and then print this
    return 0;
}

输出：

###I want to print this at the end of the line

但我希望输出是这样的（通过光标移动，而不是简单地在 printf() 中使用它）：

###s is a test lineI want to print this at the end of the line

在 C 中执行此操作的方法是什么？

Answer 1

使用 ANSI escape sequences 适合我

#include <stdio.h>

int main(void) {
    printf("One Two Three\x1b[s\r");
    //                   ^^^^^^      ESC[s ==> save cursor position
    printf("###\x1b[u");
    //         ^^^^^^                ESC[u ==> restore cursor position
    printf("FOUR FIVE SIX\n");
}

表观输出

### Two ThreeFOUR FIVE SIX

Answer 2

#include <stdio.h>
        
        int main()
        {
            printf("This is a test line");
            printf("I want to print this at the end of the line\r");
            printf("###");
             
            return 0;
        }

输出： ###s is a test lineI want to print this at the end of the line

在 C 中使用转义序列 \r 后，如何将光标移至行尾（不影响行的内容）？

How to take to cursor to the end of the line (Without disturbing the content of the line) after we use the escape sequence \r in C?

c

escaping