获取 recv() 缓冲区的一部分

Question

我有这段打印 http 服务器响应的代码，但现在我试图获取唯一的状态代码，并从那里做出决定。喜欢 :

代码：200 - 打印正常 code:404 - 未找到打印页面等等

PS: 无法使用 http 库

from socket import * 

#constants variables
target_host = 'localhost'
target_port = 80
target_dir = 'dashboard/index.html'

# create a socket object 
client = socket(AF_INET, SOCK_STREAM)  # create an INET (IPv4), STREAMing socket (TCP)
 
# connect the client 
client.connect((target_host,target_port))  
 
# send some data 
request = "GET /%s HTTP/1.1\r\nHost:%s\r\n\r\n" % (target_dir, target_host)

#Send data to the socket.
client.send(request.encode())  

# receive some data 
data = b''
while True: #while data
    buffer = client.recv(2048) #recieve a 2048 bytes data from socket
    if not buffer: #no more data, break
        break
    data += buffer #concatenate buffer data

client.close() #close buffer

#display the response
print(data.decode())

Answer 1

我会按如下方式更改接收循环：提取第一行，将其拆分，将第二个单词解释为整数。

line = b''
while True:
    c = client.recv(1)
    if not c or c=='\n':
        break
    line += c

status = -1
line = line.split()
if len(line)>=2:
  try:
    status = int(line[1])
  except:
    pass
print(status)

如果我们严重依赖try我们可以简化第二部分

try:
  status = int(line.split()[1])
except:
  status = -1
print(status)

获取 recv() 缓冲区的一部分

getting part of the recv() buffer

python

sockets

http

httpserver

websocket