试图抓取图片网址但无法使用漂亮的汤和 python

Question

我正在抓取这个 link : https://www.americanexpress.com/in/credit-cards/all-cards/?sourcecode=A0000FCRAA&cpid=100370494&dsparms=dc_pcrid_408453063287_kword_american%20express%20credit%20card_match_e&gclid=Cj0KCQiApY6BBhCsARIsAOI_GjaRsrXTdkvQeJWvKzFy_9BhDeBe2L2N668733FSHTHm96wrPGxkv7YaAl6qEALw_wcB&gclsrc=aw.ds

并获取图片 url

from urllib.request import urlopen
from bs4 import BeautifulSoup
import json


AMEXurl = ['https://www.americanexpress.com/in/credit-cards/all-cards/?sourcecode=A0000FCRAA&cpid=100370494&dsparms=dc_pcrid_408453063287_kword_american%20express%20credit%20card_match_e&gclid=Cj0KCQiApY6BBhCsARIsAOI_GjaRsrXTdkvQeJWvKzFy_9BhDeBe2L2N668733FSHTHm96wrPGxkv7YaAl6qEALw_wcB&gclsrc=aw.ds']
identity = ['filmstrip_container']

html_1 = urlopen(AMEXurl[0])
soup_1 = BeautifulSoup(html_1,'lxml')
address = soup_1.find('div',attrs={"class" : identity[0]})

for x in address.find_all('div', class_ = 'filmstrip-imgContainer'):
    print(x.find('div').get('img'))

但我得到如下输出：

None
None
None
None
None
None
None

下面是 html 代码的图像，我试图从中获取图像网址：

这是我想从中获取网址的页面部分

我想知道是否需要对代码进行任何更改，以便我获取所有图片网址。

Answer 1

试试这个

import urllib
from urllib.request import urlopen
from bs4 import BeautifulSoup
import json
import requests
import re

AMEXurl = ['https://www.americanexpress.com/in/credit-cards/all-cards/?sourcecode=A0000FCRAA&cpid=100370494&dsparms=dc_pcrid_408453063287_kword_american%20express%20credit%20card_match_e&gclid=Cj0KCQiApY6BBhCsARIsAOI_GjaRsrXTdkvQeJWvKzFy_9BhDeBe2L2N668733FSHTHm96wrPGxkv7YaAl6qEALw_wcB&gclsrc=aw.ds']
identity = ['filmstrip_container']

r = requests.get(AMEXurl[0])

html_1 = urlopen(AMEXurl[0])

soup_1 = BeautifulSoup(r.content,'lxml')

提取所有图像

images = soup_1.find_all('img', src=True)

for img in images:
    print(img['src'])

显示 png 文件的所有图像标签。

platinum_card_image=soup_1.find('img', src=re.compile('Platinum_Card\.png$'))
print(platinum_card_image.get('src'))

显示 svg 文件的所有图像标签。

platinum_card_image=soup_1.find_all('img', src=re.compile('\.svg$'))

for img in platinum_card_image:
    print(img.get('src'))

编辑

images_7 = soup_1.select('script')[8].string.split('__REDUX_STATE__ = ')
data = images_7[1]

for d in json.loads(data)["modelData"]['componentFeaturedCards']['cards']:
    print(d['imgurl'])

Answer 2

它们是从脚本标签动态加载的。您可以轻松地从响应的 .text 中对它们进行正则表达式。下面的正则表达式专门匹配你说要检索并显示在图片中的 7 张图像。

import requests, re

r = requests.get('https://www.americanexpress.com/in/credit-cards/all-cards/?sourcecode=A0000FCRAA&cpid=100370494&dsparms=dc_pcrid_408453063287_kword_american%20express%20credit%20card_match_e&gclid=Cj0KCQiApY6BBhCsARIsAOI_GjaRsrXTdkvQeJWvKzFy_9BhDeBe2L2N668733FSHTHm96wrPGxkv7YaAl6qEALw_wcB&gclsrc=aw.ds').text
p = re.compile(r'imgurl":"(.*?)"')
links = p.findall(r)
print(links)

正则表达式解释：

您是否决定使用可以匹配的更昂贵的硒

links = [i['src'] for i in driver.find_all_elements_with_css_selector('.filmstrip-imgContainer img')]

试图抓取图片网址但无法使用漂亮的汤和 python

Trying to scrape image urls but not able to get it using beautiful soup and python

python

beautifulsoup

web-scraping

python-requests

scrapinghub

提取所有图像

显示 png 文件的所有图像标签。

显示 svg 文件的所有图像标签。

编辑