在 bash 中将 stat/number 与另一个 stat/number 相除

Question

我有一个简单的问题，但我无法使用 bash，我正在使用命令行来获取我的 Pi-Hole 对 Unbound（递归 DNS ) 并且我想将缓存的查询显示为总查询的百分比，这里是获取总查询的行：

sudo unbound-control stats_noreset | awk -F '=' '/total.num.queries/ {print $NF}'

例如，这给了我 1500 我想用这条线除以这个数字：

sudo unbound-control stats_noreset | awk -F '=' '/total.num.cachehits/ {print $NF}'

例如 500 我想将其显示为：

500 33.3%

只有一行代码，没有变量。

非常感谢！我试了好几天。

编辑：根据要求，sudo unbound-control stats_noreset 的完整输出是：

sudo unbound-control stats_noreset
thread0.num.queries=1294
thread0.num.queries_ip_ratelimited=0
thread0.num.cachehits=327
thread0.num.cachemiss=967
thread0.num.prefetch=134
thread0.num.zero_ttl=0
thread0.num.recursivereplies=967
thread0.requestlist.avg=0.334242
thread0.requestlist.max=9
thread0.requestlist.overwritten=0
thread0.requestlist.exceeded=0
thread0.requestlist.current.all=0
thread0.requestlist.current.user=0
thread0.recursion.time.avg=0.080698
thread0.recursion.time.median=0.0325689
thread0.tcpusage=0
thread1.num.queries=1309
thread1.num.queries_ip_ratelimited=0
thread1.num.cachehits=342
thread1.num.cachemiss=967
thread1.num.prefetch=132
thread1.num.zero_ttl=0
thread1.num.recursivereplies=967
thread1.requestlist.avg=0.374886
thread1.requestlist.max=9
thread1.requestlist.overwritten=0
thread1.requestlist.exceeded=0
thread1.requestlist.current.all=0
thread1.requestlist.current.user=0
thread1.recursion.time.avg=0.075309
thread1.recursion.time.median=0.0322503
thread1.tcpusage=0
thread2.num.queries=1338
thread2.num.queries_ip_ratelimited=0
thread2.num.cachehits=336
thread2.num.cachemiss=1002
thread2.num.prefetch=156
thread2.num.zero_ttl=0
thread2.num.recursivereplies=1002
thread2.requestlist.avg=0.360104
thread2.requestlist.max=9
thread2.requestlist.overwritten=0
thread2.requestlist.exceeded=0
thread2.requestlist.current.all=0
thread2.requestlist.current.user=0
thread2.recursion.time.avg=0.073632
thread2.recursion.time.median=0.031425
thread2.tcpusage=0
thread3.num.queries=1258
thread3.num.queries_ip_ratelimited=0
thread3.num.cachehits=339
thread3.num.cachemiss=919
thread3.num.prefetch=127
thread3.num.zero_ttl=0
thread3.num.recursivereplies=919
thread3.requestlist.avg=0.315488
thread3.requestlist.max=9
thread3.requestlist.overwritten=0
thread3.requestlist.exceeded=0
thread3.requestlist.current.all=0
thread3.requestlist.current.user=0
thread3.recursion.time.avg=0.073834
thread3.recursion.time.median=0.0308651
thread3.tcpusage=0
total.num.queries=5199
total.num.queries_ip_ratelimited=0
total.num.cachehits=1344
total.num.cachemiss=3855
total.num.prefetch=549
total.num.zero_ttl=0
total.num.recursivereplies=3855
total.requestlist.avg=0.34673
total.requestlist.max=9
total.requestlist.overwritten=0
total.requestlist.exceeded=0
total.requestlist.current.all=0
total.requestlist.current.user=0
total.recursion.time.avg=0.075873
total.recursion.time.median=0.0317773
total.tcpusage=0
time.now=1613041718.040611
time.up=14305.501526
time.elapsed=14305.501526

thread0,1,etc..是核心，但我只对总数感兴趣。

Answer 1

我假设当你说没有变量时，你的意思是 在 shell 中没有变量。

考虑到这一点，您可以使用 awk 变量来存储中间结果：

sudo unbound-control stats_noreset | awk -F '=' ' == "total.num.queries" {queries=$NF}  == "total.num.cachehits" {hits=$NF}END{print hits, hits/queries*100"%"}'

或更易读的多行格式：

sudo unbound-control stats_noreset | 
   awk -F '=' ' == "total.num.queries" { queries = $NF }
                == "total.num.cachehits" { hits = $NF }
               END { print hits, hits / queries * 100 "%" }'

输出为：

1344 25.8511%

如果输出只需要一个小数位，可以使用printf，比如

END { printf "%d %.1f%%\n", hits, hits / queries * 100 }

在 bash 中将 stat/number 与另一个 stat/number 相除

Make a division of a stat/number from another stat/number in bash

bash

division