汇总包含多个字符串的单元格

Question

我正在尝试将 str_detect 与 sum 结合使用来添加包含字符串集的变量。如何使用下面的 AND 来检测包含 all 字符串的变量而不考虑顺序？

"|"在这种情况下有效，但不适用于“&”

可重现的例子：

data<- data.frame("order" = c("A","B","C","A:B","A:B:C","B:C"))

wrong.out <- data %>% summarise("total"=n(),
                           "A"= sum(str_detect(order, "A"), na.rm = TRUE),
                           "B"= sum(str_detect(order, "B"), na.rm = TRUE),
                           "C"= sum(str_detect(order, "C"), na.rm = TRUE),
                           "A:B"= sum(str_detect(order, "(A)&(B)"), na.rm = TRUE),
                           "A:B:C"= sum(str_detect(order, "(A)&(B)&(C)"), na.rm = TRUE))

我正在寻找如下总计，计算同时包含 A&B 或 A&B&C 的任何单元格：

expected.out <- data.frame("total" = "6",
                      "A"="3",
                       "B"="4",
                       "C"="3",
                       "A:B"="2", 
                         "A:B:C"="1")

Answer 1

对&条件单独使用str_detect。

library(dplyr)
library(stringr)

summarise("Total" = n(),
          "CD8:PD-1" = sum(str_detect(ordered, "PD-1") & 
                           str_detect(ordered, "CD8"),na.rm = TRUE),
          "CD8:PD:1:FoxP3" = sum(str_detect(ordered, "PD-1") & 
                                 str_detect(ordered, "CD8") &
                                 str_detect(ordered, "FoxP3"), na.rm = TRUE))

Answer 2

为什么不呢？

data %>% summarise("total"=n(),
                                "A"= sum(str_detect(order, "A"), na.rm = TRUE),
                                "B"= sum(str_detect(order, "B"), na.rm = TRUE),
                                "C"= sum(str_detect(order, "C"), na.rm = TRUE),
                                "A:B"= sum(str_detect(order, "A:B"), na.rm = TRUE),
                                "A:B:C"= sum(str_detect(order, "A:B:C"), na.rm = TRUE))

  total A B C A:B A:B:C
1     6 3 4 3   2     1

汇总包含多个字符串的单元格

summarise to sum cells containing multiple strings

r

stringr