QisKit：Statevector 上的差异/可视化上的无差异

Question

为什么状态向量有差异，但可视化没有差异？
是否有任何其他可视化来显示差异？

qiskit: 0.23.3
python: 3.8

circuit-1 + statevector:
q_0: 
[1.+0.j 0.+0.j] ==> +1

circuit-2 + statevector
     ┌───┐┌───┐┌───┐┌───┐┌───┐
q_0: ┤ X ├┤ H ├┤ X ├┤ H ├┤ X ├
     └───┘└───┘└───┘└───┘└───┘
[-1.+0.j -0.-0.j] ==> -1

代码示例

import numpy as np
from qiskit import *
import qiskit.tools.visualization as vis
import matplotlib. pyplot as plt
from qiskit import Aer

circ = QuantumCircuit(1)

circ.x(0)
circ.h(0)
circ.x(0)
circ.h(0)
circ.x(0)

backend = Aer.get_backend('statevector_simulator')
result = execute(circ, backend).result()
statevector = result.get_statevector()

vis.plot_bloch_multivector(statevector)
vis.plot_state_city(statevector)
vis.plot_state_qsphere(statevector)
vis.plot_state_paulivec(statevector)
circ.draw(output='mpl')
print(np.around(statevector,5))
plt.show()

两个状态向量的可视化是相等的！！

Answer 1

这对我来说似乎是一个错误（我报告了 here）

无论如何，我建议您 Kaleidoscope 将状态可视化。它有交互式图表。这是您的示例（为简洁而重构）：

from qiskit import QuantumCircuit
from qiskit.quantum_info import Statevector
from kaleidoscope import qsphere

circ = QuantumCircuit(1)

circ.x(0)
circ.h(0)
circ.x(0)
circ.h(0)
circ.x(0)

state = Statevector.from_instruction(circ)
qsphere(state)

与另一个例子比较颜色：

circ = QuantumCircuit(1)

state = Statevector.from_instruction(circ)
qsphere(state)

颜色的不同就是相位。第一种情况是π.

QisKit：Statevector 上的差异/可视化上的无差异

QisKit: Difference on Statevector / No Difference on Vizualization

python

visualization

qiskit