如何增加 URL 字符串中特定参数的数字部分？

Question

这是我的具体示例：

param1 = 'XXXXXXXXXXX'
param2 = 'XXXX'
param3 = 'XXXX'
param4 = 'XXXX'
param5 = 'XXXX'
param6 = 'XXXX'
#param7 below holds the (always numerical) value that needs to be incremented so that param7 = '2' in the next pass through
param7 = '1' 

#url of fantasy league with statistics
url = ('https://www.fantrax.com/fantasy/league/'+param1+'/players'
   +';positionOrGroup='+param2
   +';miscDisplayType='+param3
   +';seasonOrProjection=SEASON_9'+param4
   #so on and so forth
   +';parameterThatNeedsIncremented'+param7)

browser.get(url)

我需要本例中 param7 的数值在每次传递到 param7 = '30' 之前增加计数 1。

有什么方法可以创建一个包含值“1”到“30”的列表或字典，并告诉 param7 在索引 + 1 处使用 use move through the dict？

Answer 1

您可以使用带有 range() 函数的 for 循环，其中 returns 一个数字序列，从指定的第一个数字开始，递增 1（默认情况下），并在第二个指定数字之前停止。

param1 = 'XXXXXXXXXXX'
param2 = 'XXXX'
param3 = 'XXXX'
param4 = 'XXXX'
param5 = 'XXXX'
param6 = 'XXXX'

for param7 in range(1, 31):
    param7 = str(param7) # If it needs to be string
    #url of fantasy league with statistics
    url = ('https://www.fantrax.com/fantasy/league/'+param1+'/players'
        +';positionOrGroup='+param2
        +';miscDisplayType='+param3
        +';seasonOrProjection=SEASON_9'+param4
        #so on and so forth
        +';parameterThatNeedsIncremented'+param7)

    browser.get(url)

如何增加 URL 字符串中特定参数的数字部分？

How would I increment the numerical portion of a specific parameter in a URL string?

html

python

macos

automation

web-scraping