如何在 has_many 上实现搜索:通过关联
How to implemet search with ransack on a has_many :through association
这是我目前所做的
class Business < ApplicationRecord
has_many :locations
has_many :continent, through: :locations
...........
class Continent < ApplicationRecord
has_many :locations
has_many :businesses, through: :locations
..............
class Location < ApplicationRecord
belongs_to :continent
belongs_to :business
end
#搜索表单
<%= search_form_for @q do |f| %>
<%= f.select :continent_id_eq, options_from_collection_for_select(Continent.all.order(:name), :id, :name, @q.continent_id_eq), { }, {class: ''} %>
<%= f.search_field :name_cont %>
我已经创建了记录并给出了适当的association.s表格,当我从select列表中查询一个大陆的商家时,它没有查询。没有显示错误
这是我从搜索参数中得到的
localhost:3000/businesses?q[continent_id_eq]=1&q[name_cont]=&commit=Search
这是控制台日志
Business Load (1.6ms) SELECT DISTINCT "businesses".* FROM "businesses" LEFT OUTER JOIN "locations" ON "locations"."business_id" = "businesses"."id" LEFT OUTER JOIN "continents" ON "continents"."id" = "locations"."continent_id" WHERE "continents"."id" = 3
我做错了什么
由于 Business
模型 has_many :continents
,您将需要使用复数形式 continents
,因此:
<%= f.select :continents_id_eq, options_from_collection_for_select(Continent.all.order(:name), :id, :name, @q.continent_id_eq), { }, {class: ''} %>
这是我目前所做的
class Business < ApplicationRecord
has_many :locations
has_many :continent, through: :locations
...........
class Continent < ApplicationRecord
has_many :locations
has_many :businesses, through: :locations
..............
class Location < ApplicationRecord
belongs_to :continent
belongs_to :business
end
#搜索表单
<%= search_form_for @q do |f| %>
<%= f.select :continent_id_eq, options_from_collection_for_select(Continent.all.order(:name), :id, :name, @q.continent_id_eq), { }, {class: ''} %>
<%= f.search_field :name_cont %>
我已经创建了记录并给出了适当的association.s表格,当我从select列表中查询一个大陆的商家时,它没有查询。没有显示错误
这是我从搜索参数中得到的
localhost:3000/businesses?q[continent_id_eq]=1&q[name_cont]=&commit=Search
这是控制台日志
Business Load (1.6ms) SELECT DISTINCT "businesses".* FROM "businesses" LEFT OUTER JOIN "locations" ON "locations"."business_id" = "businesses"."id" LEFT OUTER JOIN "continents" ON "continents"."id" = "locations"."continent_id" WHERE "continents"."id" = 3
我做错了什么
由于 Business
模型 has_many :continents
,您将需要使用复数形式 continents
,因此:
<%= f.select :continents_id_eq, options_from_collection_for_select(Continent.all.order(:name), :id, :name, @q.continent_id_eq), { }, {class: ''} %>