如何使用 Python 提取列表中的某些值？

Question

我有以下列表：

URLs = [ 
  { "category": "A12",
    "base_url": "https://whosebug.com",
    "endpoints" : [ 
        { "name": "Online", "path": "/a2"},
        { "name": "Offline ", "path": "/b2"}
    ]
  },
  { "category": "A13",
    "base_url": "https://google.com",
    "endpoints" : [ 
        { "name": "Online", "path": "/abc1"},
        { "name": "Offline", "path": "/abc2"}
    ]
  },
  { "category": "A14",
    "base_url": "http://stackover.com",
    "endpoints" : [ 
        { "name": "Check", "path": "/bbc3"}
    ]
  }
]

我只想从列表中提取基本 URL 和端点路径并打印或另存为另一个变量。输出应如下所示：

https://whosebug.com/a2
https://whosebug.com/b2
https://google.com/abc1
https://google.com/abc2
http://stackover.com/bbc3

我该怎么做？

Answer 1

所以你有一个 list 并且在列表中有一个 dictionary。这将是最简单的方法：

 for url in URLs:
        print(url["base_url"])

Answer 2

这是解决方案

output = []

for url_map in URLs:
    for endpoint in url_map['endpoints']:
        output.append(url_map['base_url'] + endpoint['path'])

Answer 3

列表理解会给你想要的输出。

URLs = [ 
  ...
]

res = [i["base_url"] + j["path"] for i in URLs for j in i["endpoints"]]

结果如下所示：

['https://whosebug.com/a2', 'https://whosebug.com/b2', 'https://google.com/abc1', 'https://google.com/abc2', 'http://stackover.com/bbc3']

如何使用 Python 提取列表中的某些值？

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