只接受整数的代码
Code for only accepting integers
import javax.swing.*;
import java.awt.*;
public class JCD {
public static void main(String[] args) {
String input, inputs;
int input1, input2;
input = JOptionPane.showInputDialog("Enter first number");
inputs = JOptionPane.showInputDialog("Enter second number");
input1 = Integer.parseInt(input);
input2 = Integer.parseInt(inputs);
JOptionPane.showMessageDialog(null, "The GCD of two numbers " + input
+ "and" + inputs + " is: " + findGCD(input1, input2));
}// close void
private static int findGCD(int number1, int number2) {
// base case
if (number2 == 0) {
return number1;
}// end if
return findGCD(number2, number1 % number2);
}// end static
} // close class
我可以添加什么以使其只接受整数?如果没有给出一个整数那么它会回去再问一次.....
把你的输入请求放在一个while语句中,检查它是否是一个int,如果不是则重复循环,否则退出。为您的两个输入执行此操作。
像这样
public static void main(String[] args) {
String input=null, inputs=null;
int input1 = 0, input2=0;
boolean err=true;
do{
try{
input = JOptionPane.showInputDialog("Enter first number");
input1 = Integer.parseInt(input);
err=false;
}catch(NumberFormatException e){
e.printStackTrace();
}
}while(err);
err=true;
do{
try{
inputs = JOptionPane.showInputDialog("Enter second number");
input2 = Integer.parseInt(inputs);
err=false;
}catch(NumberFormatException e){
e.printStackTrace();
}
}while(err);
JOptionPane.showMessageDialog(null, "The GCD of two numbers " + input
+ "and" + inputs + " is: " + findGCD(input1, input2));
}
请注意,此解决方案要求您在声明变量时对其进行初始化
String input = null, inputs = null;
int input1=0, input2=0;
你应该试试 "try and catch"。
输入 = JOptionPane.showInputDialog("Enter first number");
输入=JOptionPane.showInputDialog("Enter second number");
try {
input1=Integer.parseInt(input);
input2=Integer.parseInt(inputs);
// establish and use the variables if the characters inserted are numbers
}
catch(NumberFormatException e){
JOptionPane.showMessageDialog(null, e+ "is not a number");
//display a warning to le the user know
}
你可以使用这样的东西:-
boolean inputAccepted = false;
while(!inputAccepted) {
try {
input1=Integer.parseInt(input);
input2=Integer.parseInt(inputs);
inputAccepted = true;
} catch(NumberFormatException e) {
JOptionPane.showMessageDialog("Please input a number only");
}
... do stuff with good input value
}
import javax.swing.*;
import java.awt.*;
public class JCD {
public static void main(String[] args) {
String input, inputs;
int input1, input2;
input = JOptionPane.showInputDialog("Enter first number");
inputs = JOptionPane.showInputDialog("Enter second number");
input1 = Integer.parseInt(input);
input2 = Integer.parseInt(inputs);
JOptionPane.showMessageDialog(null, "The GCD of two numbers " + input
+ "and" + inputs + " is: " + findGCD(input1, input2));
}// close void
private static int findGCD(int number1, int number2) {
// base case
if (number2 == 0) {
return number1;
}// end if
return findGCD(number2, number1 % number2);
}// end static
} // close class
我可以添加什么以使其只接受整数?如果没有给出一个整数那么它会回去再问一次.....
把你的输入请求放在一个while语句中,检查它是否是一个int,如果不是则重复循环,否则退出。为您的两个输入执行此操作。
像这样
public static void main(String[] args) {
String input=null, inputs=null;
int input1 = 0, input2=0;
boolean err=true;
do{
try{
input = JOptionPane.showInputDialog("Enter first number");
input1 = Integer.parseInt(input);
err=false;
}catch(NumberFormatException e){
e.printStackTrace();
}
}while(err);
err=true;
do{
try{
inputs = JOptionPane.showInputDialog("Enter second number");
input2 = Integer.parseInt(inputs);
err=false;
}catch(NumberFormatException e){
e.printStackTrace();
}
}while(err);
JOptionPane.showMessageDialog(null, "The GCD of two numbers " + input
+ "and" + inputs + " is: " + findGCD(input1, input2));
}
请注意,此解决方案要求您在声明变量时对其进行初始化
String input = null, inputs = null;
int input1=0, input2=0;
你应该试试 "try and catch"。
输入 = JOptionPane.showInputDialog("Enter first number");
输入=JOptionPane.showInputDialog("Enter second number");
try {
input1=Integer.parseInt(input);
input2=Integer.parseInt(inputs);
// establish and use the variables if the characters inserted are numbers
}
catch(NumberFormatException e){
JOptionPane.showMessageDialog(null, e+ "is not a number");
//display a warning to le the user know
}
你可以使用这样的东西:-
boolean inputAccepted = false;
while(!inputAccepted) {
try {
input1=Integer.parseInt(input);
input2=Integer.parseInt(inputs);
inputAccepted = true;
} catch(NumberFormatException e) {
JOptionPane.showMessageDialog("Please input a number only");
}
... do stuff with good input value
}