在一个范围内将 16 位数字的前 15 位数字增加 1
Increase the first 15 digits of a 16 digit number by 1 within a range
背景
我正在努力确保生成唯一的 credit card number。 credit card number 需要 16 位长 ，最后一位等于 checksum，在本例中为 self.checksum = 1.
credit card number的前6位必须是400000。
由于在这种情况下最后一位数字必须等于 checksum 或 1，我相信我需要以某种方式在我的代码中实现一个范围以指示何时 maximum credit card number has been issued.在这种情况下，最大值 credit card number 是 40000009999999991。之后的任何内容都会更改前 6 位数字。
虽然当前解决方案“有效”，但它仅通过将 10 添加到在 __init__ 中初始化为 self.credit_card_number = 4000000000000001.[=27 的第一个可能的 credit card number 来实现=]
需要帮助
我正在寻求帮助，利用我现有的代码并实现某种范围，当范围内的最后一个 credit card number 发出时，它会发出警报。
from random import randrange
class Accounts:
def __init__(self):
self.accounts_list = []
self.all_accounts = dict()
self.balance = 0
# Initial credit card number
self.credit_card_number = 4000000000000001
# Checksum is the last digit (16th) in the credit card number.
self.checksum = 1
# Pin number is generated in account_creation
self.pin = None
def main_menu(self):
while True:
main_menu_choice = input('1. Create an account\n'
'2. Log into account\n'
'0. Exit\n')
if main_menu_choice == '1':
self.account_creation()
def account_creation(self):
# Create credit card number ensuring it is unique by adding 1 to initialized value.
if len(self.accounts_list) == 0:
self.credit_card_number = self.credit_card_number
else:
self.credit_card_number = self.credit_card_number
self.credit_card_number = self.credit_card_number + 10
# Create pin number.
pin = int(format(randrange(0000, 9999), '04d'))
# Add credit card number to list used in the above if statement.
self.accounts_list.append(self.credit_card_number)
# Add the credit card number, pin, and balance to dictionary.
self.all_accounts[self.credit_card_number] = {'pin': pin, 'balance': self.balance}
# Print the output to make sure everything is OK.
print(self.accounts_list)
# Print the output to make sure everything is OK.
print(self.all_accounts)
print(f'\n'
f'Your card has been created\n'
f'Your card number:\n'
f'{self.credit_card_number}\n'
f'Your card PIN:\n'
f'{pin}'
f'\n')
Accounts().main_menu()
你能更新你的 init 来生成信用卡吗：
def __init__(self):
# do you stuff
self.credit_card_first_6 = '400000'
self.checksum = '1'
# this will be used to create a unique credit card
self.count = 0
# middle numbers MUST be smaller than this
self.max_count = 1000000000
def account_creation(self):
#### do your stuff
# for this user they have a unique 9 digits in the middle
# this is then zero padded using zfill
unique_id = str(self.count).zfill(9)
# create the full credit card number
# note: store each bit as a str so we can concat then convert to int
credit_card_number = int(self.credit_card_first_6 + unique_id + checksum)
self.count += 1
# update your init values when your limit is reached
if self.count >= self.max_count:
self.count = 0
self.credit_card_first_6 = str(int(self.credit_card_first_6) + 1)
由于您将 Matt 的回答标记为有效，我添加了一个快速重构，其中包含一些可能对您有用的额外代码。
class Account:
balance = 0
__pin = None # this are
__number = None # private members
def __eq__(self, other):
return self.__number == other
def is_pin(self, pin):
return self.__pin == pin
def number(self):
return self.__number
# adding a 'is not none' makes
# it a 'write only once' variable,
# if a 'none' text is added as a input
# text is added not a None type
def set_pin(self, pin):
if self.__pin is None:
self.__pin = pin
return True
return False
def set_number(self, num):
if self.__number is None \
and len(str(num)) == 16:
self.__number = num
return True
return False
# eeextra simple checksum
def checksum(self):
ck_sum = 0
for i in str(self.__number):
ck_sum += int(i)
return int(str(ck_sum)[-1])
class Accounts:
base_num = 4000000000000000
def __init__(self):
self.accounts = []
self.num_offset = 0
@staticmethod
def dialog_choice():
choice = input(
'1. Create an account\n'
'2. Log into account\n'
'0. Exit \n \n'
)
return choice
def next_card_num(self):
self.num_offset += 1
return self.base_num + self.num_offset
def dialog_acount_creation(self):
card_pin = input('New pin ->')
card_num = self.next_card_num()
print('Card number ->', card_num)
return card_num, card_pin
@staticmethod
def dialog_login():
card_num = input('Card number ->')
card_pin = input('Card pin ->')
return int(card_num), card_pin
@staticmethod
def dialog_error(*args):
print('Error on acount', args[0])
def main_loop(self):
dia_map = {
'1': self.dialog_acount_creation,
'2': self.dialog_login,
}
cho_map = {
'1': self.account_creation,
'2': self.account_login,
}
err_map = {
'1': self.dialog_error,
'2': self.dialog_error,
}
while True:
o = self.dialog_choice()
if o == '0':
break
if o in cho_map:
q_dialog = dia_map[o]()
q_done = cho_map[o](*q_dialog)
if not q_done:
err_map[o](*q_dialog)
else:
print('Invalid option')
def account_login(self, num, pin):
for acc in self.accounts:
if acc == num and acc.is_pin(pin):
print('You are logged in !')
return True
return False
def account_creation(self, num, pin):
new_accaunt = Account()
new_accaunt.set_number(num)
new_accaunt.set_pin(pin)
self.accounts.append(new_accaunt)
return True
if __name__ == '__main__':
h_acc = Accounts()
h_acc.account_creation(4000000000000000, '1234')
h_acc.main_loop()
背景
我正在努力确保生成唯一的 credit card number。 credit card number 需要 16 位长 ，最后一位等于 checksum，在本例中为 self.checksum = 1.
credit card number的前6位必须是400000。
由于在这种情况下最后一位数字必须等于 checksum 或 1，我相信我需要以某种方式在我的代码中实现一个范围以指示何时 maximum credit card number has been issued.在这种情况下，最大值 credit card number 是 40000009999999991。之后的任何内容都会更改前 6 位数字。
虽然当前解决方案“有效”，但它仅通过将 10 添加到在 __init__ 中初始化为 self.credit_card_number = 4000000000000001.[=27 的第一个可能的 credit card number 来实现=]
需要帮助
我正在寻求帮助，利用我现有的代码并实现某种范围，当范围内的最后一个 credit card number 发出时，它会发出警报。
from random import randrange
class Accounts:
def __init__(self):
self.accounts_list = []
self.all_accounts = dict()
self.balance = 0
# Initial credit card number
self.credit_card_number = 4000000000000001
# Checksum is the last digit (16th) in the credit card number.
self.checksum = 1
# Pin number is generated in account_creation
self.pin = None
def main_menu(self):
while True:
main_menu_choice = input('1. Create an account\n'
'2. Log into account\n'
'0. Exit\n')
if main_menu_choice == '1':
self.account_creation()
def account_creation(self):
# Create credit card number ensuring it is unique by adding 1 to initialized value.
if len(self.accounts_list) == 0:
self.credit_card_number = self.credit_card_number
else:
self.credit_card_number = self.credit_card_number
self.credit_card_number = self.credit_card_number + 10
# Create pin number.
pin = int(format(randrange(0000, 9999), '04d'))
# Add credit card number to list used in the above if statement.
self.accounts_list.append(self.credit_card_number)
# Add the credit card number, pin, and balance to dictionary.
self.all_accounts[self.credit_card_number] = {'pin': pin, 'balance': self.balance}
# Print the output to make sure everything is OK.
print(self.accounts_list)
# Print the output to make sure everything is OK.
print(self.all_accounts)
print(f'\n'
f'Your card has been created\n'
f'Your card number:\n'
f'{self.credit_card_number}\n'
f'Your card PIN:\n'
f'{pin}'
f'\n')
Accounts().main_menu()
你能更新你的 init 来生成信用卡吗：
def __init__(self):
# do you stuff
self.credit_card_first_6 = '400000'
self.checksum = '1'
# this will be used to create a unique credit card
self.count = 0
# middle numbers MUST be smaller than this
self.max_count = 1000000000
def account_creation(self):
#### do your stuff
# for this user they have a unique 9 digits in the middle
# this is then zero padded using zfill
unique_id = str(self.count).zfill(9)
# create the full credit card number
# note: store each bit as a str so we can concat then convert to int
credit_card_number = int(self.credit_card_first_6 + unique_id + checksum)
self.count += 1
# update your init values when your limit is reached
if self.count >= self.max_count:
self.count = 0
self.credit_card_first_6 = str(int(self.credit_card_first_6) + 1)
由于您将 Matt 的回答标记为有效，我添加了一个快速重构，其中包含一些可能对您有用的额外代码。
class Account:
balance = 0
__pin = None # this are
__number = None # private members
def __eq__(self, other):
return self.__number == other
def is_pin(self, pin):
return self.__pin == pin
def number(self):
return self.__number
# adding a 'is not none' makes
# it a 'write only once' variable,
# if a 'none' text is added as a input
# text is added not a None type
def set_pin(self, pin):
if self.__pin is None:
self.__pin = pin
return True
return False
def set_number(self, num):
if self.__number is None \
and len(str(num)) == 16:
self.__number = num
return True
return False
# eeextra simple checksum
def checksum(self):
ck_sum = 0
for i in str(self.__number):
ck_sum += int(i)
return int(str(ck_sum)[-1])
class Accounts:
base_num = 4000000000000000
def __init__(self):
self.accounts = []
self.num_offset = 0
@staticmethod
def dialog_choice():
choice = input(
'1. Create an account\n'
'2. Log into account\n'
'0. Exit \n \n'
)
return choice
def next_card_num(self):
self.num_offset += 1
return self.base_num + self.num_offset
def dialog_acount_creation(self):
card_pin = input('New pin ->')
card_num = self.next_card_num()
print('Card number ->', card_num)
return card_num, card_pin
@staticmethod
def dialog_login():
card_num = input('Card number ->')
card_pin = input('Card pin ->')
return int(card_num), card_pin
@staticmethod
def dialog_error(*args):
print('Error on acount', args[0])
def main_loop(self):
dia_map = {
'1': self.dialog_acount_creation,
'2': self.dialog_login,
}
cho_map = {
'1': self.account_creation,
'2': self.account_login,
}
err_map = {
'1': self.dialog_error,
'2': self.dialog_error,
}
while True:
o = self.dialog_choice()
if o == '0':
break
if o in cho_map:
q_dialog = dia_map[o]()
q_done = cho_map[o](*q_dialog)
if not q_done:
err_map[o](*q_dialog)
else:
print('Invalid option')
def account_login(self, num, pin):
for acc in self.accounts:
if acc == num and acc.is_pin(pin):
print('You are logged in !')
return True
return False
def account_creation(self, num, pin):
new_accaunt = Account()
new_accaunt.set_number(num)
new_accaunt.set_pin(pin)
self.accounts.append(new_accaunt)
return True
if __name__ == '__main__':
h_acc = Accounts()
h_acc.account_creation(4000000000000000, '1234')
h_acc.main_loop()