SQL 服务器:连接 XML 列的节点值

SQL SERVER: concatenate node values of XML column

我有以下 table 包含 XML 中的一列:

Id Label Details
1 Test1 <terms><destination><email>email11@foo.com</email><email>email12@foo.com</email></destination><content>blabla</content></terms>
2 Test2 <terms><destination><email>email21@foo.com</email><email>email22@foo.com</email></destination><content>blabla</content></terms>

我想要一个产生以下输出的查询:

Id Label Destination
1 Test1 email11@foo.com, email12@foo.com
2 Test2 email21@foo.com, email22@foo.com

关于如何将 XML 电子邮件节点值连接为相关列(Id 和标签)中的列的任何线索? 先谢谢了

请尝试以下解决方案。

由于未提供 DDL 和示例数据总体, 假设 Details 列是 XML 数据类型。

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, Label VARCHAR(20), Details XML);
INSERT INTO @tbl (Label, Details) VALUES
('Test1',N'<terms><destination><email>email11@foo.com</email><email>email12@foo.com</email></destination><content>blabla</content></terms>'),
('Test2',N'<terms><destination><email>email21@foo.com</email><email>email22@foo.com</email></destination><content>blabla</content></terms>');
-- DDL and sample data population, end

SELECT ID, Label 
    , REPLACE(Details.query('data(/terms/destination/email/text())').value('.','VARCHAR(MAX)'), SPACE(1), ', ') AS Destination
FROM @tbl;

输出

+----+-------+----------------------------------+
| ID | Label |           Destination            |
+----+-------+----------------------------------+
|  1 | Test1 | email11@foo.com, email12@foo.com |
|  2 | Test2 | email21@foo.com, email22@foo.com |
+----+-------+----------------------------------+
select ID, Label,
    stuff(
        details.query('for $step in /terms/destination/email/text() return concat(", ", string($step))')
        .value('.', 'nvarchar(max)'),
    1, 2, '')
from @tbl;