如何在 NgRx 中获取动作参数？

Question

我发送带参数的操作并替换 (block.id)?

上的 (9)

 this.store.dispatch(RegistryActions.LoadRegistryLayersAction(this.block));

如何让这个参数生效？

  loadRegistriesLayers$: Observable<Action> = createEffect(() =>
    this.actions$.pipe(
      ofType(RegistryActions.LoadRegistryLayersAction),
      switchMap(() =>
        from(this.registryService.getRegistryPolygonsPolygons(9)).pipe(
          map((layers: { [key: string]: RegistryLayerItemGeneric[] }) => {
            return RegistryActions.SuccessLoadRegistryLayersAction({
              payload: layers,
            });
          }),
          catchError((error: Error) => {
            return of(RegistryActions.ErrorRegistryLayersAction(error));
          })
        )
      )
    )
  );

Answer 1

您应该可以在 switchMap 中访问它，如下所示：

switchMap((action: {..your type}) => 
    from...

如何在 NgRx 中获取动作参数？

How to get action parameter in effect NgRx?

ngrx

ngrx-effects

angular