If Sunday then show Week rest else present in oracle 报告

Question

嗨，亲爱的，我在 oracle 报告中工作，我有一个列 ATT_DATE，其中有下一个月的日期我有：我创建这样的函数的日期

begin
  RETURN TO_CHAR(:ATT_DATE, 'DAY');
end;

它给了我出现在 :ATT_DATE 中的日期现在我想再做一个函数来检查 SUNDAY 然后给我两个这样的东西 if Sunday than Weekly Rest else Present 在 :Status 列我写了这段代码

function M_DAY2Formula return CHAR is
begin
  IF TO_CHAR(:ATT_DATE, 'DAY') = 'SUNDAY' THEN
     RETURN 'WEEK REST';
  ELSE
     RETURN 'PRESENT';
  END IF;
end;

但它从不占用星期日它在所有的日子里都给现在

Answer 1

我认为大约是 TRIM。请参阅以下示例：

SQL> with dates as
  2    (select trunc(sysdate, 'iw') + level - 1 datum
  3     from dual
  4     connect by level <= 10
  5    )
  6  select datum,
  7         to_char(datum, 'DAY') dan,
  8         to_char(datum, 'DAY', 'nls_date_language = english') dan2,
  9         --
 10         length(to_char(datum, 'DAY', 'nls_date_language = english')) len_dan2,
 11         --
 12         case when to_char(datum, 'DAY', 'nls_date_language = english') = 'SUNDAY' then 'Week rest'
 13              else 'Present'
 14         end status,
 15         --
 16         case when trim(to_char(datum, 'DAY', 'nls_date_language = english')) = 'SUNDAY' then 'Week rest'
 17              else 'Present'
 18         end status2
 19  from dates
 20  order by datum;

DATUM      DAN         DAN2        LEN_DAN2 STATUS    STATUS2
---------- ----------- --------- ---------- --------- ---------
15.02.2021 PONEDJELJAK MONDAY             9 Present   Present
16.02.2021 UTORAK      TUESDAY            9 Present   Present
17.02.2021 SRIJEDA     WEDNESDAY          9 Present   Present
18.02.2021 ČETVRTAK    THURSDAY           9 Present   Present
19.02.2021 PETAK       FRIDAY             9 Present   Present
20.02.2021 SUBOTA      SATURDAY           9 Present   Present
21.02.2021 NEDJELJA    SUNDAY             9 Present   Week rest
22.02.2021 PONEDJELJAK MONDAY             9 Present   Present
23.02.2021 UTORAK      TUESDAY            9 Present   Present
24.02.2021 SRIJEDA     WEDNESDAY          9 Present   Present

10 rows selected.

SQL>

换句话说：

如果您的日期语言不是英语，则无法将其与“SUNDAY”（在我的示例中是 dan）进行比较
如果语言没有问题，为什么第一个 case（status 列）不能正常工作？因为 length - 看到了吗？无论是哪一天，在所有情况下长度都是 9。
因此，trim DAY 值然后按预期工作

或者，在 Reports Builder 中：

function M_DAY2Formula return CHAR is
begin
  IF trim(TO_CHAR(:ATT_DATE, 'DAY')) = 'SUNDAY' THEN     --> TRIM, here
     RETURN 'WEEK REST';
  ELSE
     RETURN 'PRESENT';
  END IF;
end;

Answer 2

什么代码适合我

function M_DAY3Formula return Char is
a varchar2(40);
B varchar2(40);
begin
  select RTRIM(to_char(:ATT_DATE,'DAY')) into a from dual;
    IF A = 'SUNDAY'
        THEN B := 'WEEK REST';
    ELSE B := 'PRESENT';
        END IF;
    return B;
end;

If Sunday then show Week rest else present in oracle 报告

If Sunday then show Week rest else present in oracle reports

oracle

oracle11g

oraclereports