将8个点转换为一个矩形

Question

我在创建矩形的图片框上通过 8 个点画了 4 条线。

            float xnum = 0.580481F;
            float ynum = 0.373782F;
            float znum = 0.419519F;
            float wnum = 0.219629F;

            PointF wnum1 = new PointF(1024, wnum * 1024);
            PointF wnum2 = new PointF(0, wnum * 1024);

            PointF xnum1 = new PointF(xnum * 1024, 1024);
            PointF xnum2 = new PointF(xnum * 1024, 0);

            PointF ynum1 = new PointF(1024, ynum * 1024);
            PointF ynum2 = new PointF(0, ynum * 1024);

            PointF znum1 = new PointF(znum * 1024, 1024);
            PointF znum2 = new PointF(znum * 1024, 0);

            e.Graphics.DrawLine(pen1, wnum1, wnum2);
            e.Graphics.DrawLine(pen1, znum1, znum2);
            e.Graphics.DrawLine(pen1, xnum1, xnum2);
            e.Graphics.DrawLine(pen1, ynum1, ynum2);

有没有办法直接从我的8个点中画出矩形？

Answer 1

要绘制矩形，您需要四个点。你要问的是找到由八个不同点描述的一组线的交点，并绘制生成的多边形。当这样说时，它就变成了通过数学计算的问题：

private void Form1_Paint(object sender, PaintEventArgs e)
{
    using (var pen1 = new Pen(Color.Black))
    {
        float xnum = 0.580481F;
        float ynum = 0.373782F;
        float znum = 0.419519F;
        float wnum = 0.219629F;

        PointF wnum1 = new PointF(1024, wnum * 1024);
        PointF wnum2 = new PointF(0, wnum * 1024);

        PointF xnum1 = new PointF(xnum * 1024, 1024);
        PointF xnum2 = new PointF(xnum * 1024, 0);

        PointF ynum1 = new PointF(1024, ynum * 1024);
        PointF ynum2 = new PointF(0, ynum * 1024);

        PointF znum1 = new PointF(znum * 1024, 1024);
        PointF znum2 = new PointF(znum * 1024, 0);

        // Given the four lines, find the intersection points that mark the corners of the polygon
        PointF[] points = new PointF[]
        {
            LineLineIntersection(wnum1, wnum2, xnum1, xnum2),
            LineLineIntersection(ynum1, ynum2, xnum1, xnum2),
            LineLineIntersection(ynum1, ynum2, znum1, znum2),
            LineLineIntersection(wnum1, wnum2, znum1, znum2),
        };
        e.Graphics.DrawPolygon(pen1, points);
    }
}

static PointF LineLineIntersection(PointF line1pt1, PointF line1pt2, PointF line2pt1, PointF line2pt2)
{
    // Calculate the formula for the first line
    float a1 = line1pt2.Y - line1pt1.Y;
    float b1 = line1pt1.X - line1pt2.X;
    float c1 = a1 * (line1pt1.X) + b1 * (line1pt1.Y);

    // Calculate the formula for the second line
    float a2 = line2pt2.Y - line2pt1.Y;
    float b2 = line2pt1.X - line2pt2.X;
    float c2 = a2 * (line2pt1.X) + b2 * (line2pt1.Y);

    float determinant = a1 * b2 - a2 * b1;

    if (determinant == 0)
    {
        // The two lines are parallel, there is no intersection (or they're the same line)
        throw new Exception("Parallel lines");
    }
    else
    {
        // Calculate the point of intersection
        float x = (b2 * c1 - b1 * c2) / determinant;
        float y = (a1 * c2 - a2 * c1) / determinant;
        return new PointF(x, y);
    }
}

将8个点转换为一个矩形

Convert 8 points to a rectangle

c#

math

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