如何对 sql db2-400 中的列值进行排序？

Question

我有 10 列具有相似的信息，当大于 0 时，我想将它们升序排列。
例如，从这个：

A1	A2	A3	A4	A5	A6	A7	A8	A9	A0
00	01	00	09	08	05	00	02	06	03

为此：

A1	A2	A3	A4	A5	A6	A7	A8	A9	A0
01	02	03	05	06	08	09	00	00	00

我一直在尝试 min 和 max 功能，但无济于事。

Answer 1

您可以取消数据透视并重新聚合：一种方法是：

select max(case when seqnum = 1 then a end) as a1,
       max(case when seqnum = 2 then a end) as a2,
       . . .
from (select a.a,
             row_number() over (order by a desc) as seqnum
      from (select a1 as a from t union all
            select a2 from t union all
            select a3 from t union all
            . . .
           ) a
     ) a;

Answer 2

with
base (key, a1, a2, a3, a4, a5, a6, a7, a8, a9, a0) as (
  values
  (1, '00', '01', '00', '09', '08', '05', '00', '02', '06', '03'),
  (2, '08', '02', '00', '06', '01', '02', '00', '04', '03', '09')
),
ordered (k, value, seq) as (
  select
    key,value,rownumber() over(partition by key order by nullif(value,'00')) seq
  from base cross
    join lateral (values a1,a2,a3,a4,a5,a6,a7,a8,a9,a0) v(value)
)
select
  key,
  (select value from ordered o where (k, seq) = (key, 1)) A1,
  (select value from ordered o where (k, seq) = (key, 2)) A2,
  (select value from ordered o where (k, seq) = (key, 3)) A3,
  (select value from ordered o where (k, seq) = (key, 4)) A4,
  (select value from ordered o where (k, seq) = (key, 5)) A5,
  (select value from ordered o where (k, seq) = (key, 6)) A6,
  (select value from ordered o where (k, seq) = (key, 7)) A7,
  (select value from ordered o where (k, seq) = (key, 8)) A8,
  (select value from ordered o where (k, seq) = (key, 9)) A9,
  (select value from ordered o where (k, seq) = (key, 10)) A0
from base

如何对 sql db2-400 中的列值进行排序？

How to sort columns values in sql db2-400?

sql

db2-400