计数器未递增 Java

Question

我创建了一个名为 attemptCount 的变量，我在 0 处启动它，每次玩家尝试输入不可用的方向时都应该递增。我运行调试器和变量重置为 0 一旦我尝试再次键入相同的方向。变量 attemptCount 未在本地声明，而是在游戏方法中设置。任何想法为什么计数器重置而不是递增？我尝试将 attempCount 设置为 static 并尝试创建一个新变量来增加 attemptCount 例如counter = attempCounter++ 但 none 有效。我还查看了另一个已回答的问题，但无法理解在这种情况下我将如何应用它。任何人都可以阐明我做错了什么吗？

public class Game implements java.io.Serializable {
    private final String resourcePath;
    private final ClassLoader cl;
    private World world;
    private List<Ghost> ghosts = new ArrayList<>();
    private List<MiniGhost> miniGhosts = new ArrayList<>();
    private Map<String, List<? extends Items>> items = new HashMap<>();
    private List<Weapon> weapons;
    private final SaveGame SaveGame = new SaveGame();
    private Ghost currentGhost;
    private final Random r = new Random();
    private final String divider = "***************************************" +
            "*********************************************************";
    private Player player;
    private HauntingJFrame jFrame;
    SaveGame save = new SaveGame();
    private final transient FileReader fileReader = new FileReader();
    private MusicPlayer mp;
    private MusicPlayer soundEffect;
    private MusicPlayer walkEffect;
    private MusicPlayer keyboardEffect;
    private MusicPlayer paperFalling;
    private int guessCounter = 0;
    boolean isGameRunning = true;
    String moveGuide = "To move type: Go North, Go East, Go South, or Go West";
    String currentRoom;
    private String currentLoc;
    private boolean isSound = true;
    private int attemptCount;

    public void changeRoom(boolean isValidInput, String[] input, int attemptCount) throws
            IOException, InterruptedException {
        while (isValidInput) {
            String normalize = normalizeText(input[1]);
            try {
                if (world.getCurrentRoom().roomExits.containsKey(normalize)) {
                    player.setMostRecentExit(normalize);
                    world.setCurrentRoom(world.getCurrentRoom().roomExits.get(normalize));
                    isValidInput = false;
                    if (isSound) {
                        walkEffect.playSoundEffect();
                    }
                    Thread.sleep(1800);
                    narrateRooms(world.getCurrentRoom().getDescription(), Color.red);
                    updateCurrentRoom();
                } else {
                    replaceGameWindowWithColorText("You hit a wall. Try again.\n ", Color.RED);
                    attemptCount++;
                    System.out.println(attemptCount);
                    if (attemptCount >= 2) {
                        appendToGameWindowsWithColorNoSound("\n", Color.WHITE);
                        openMap();
                        appendToGameWindowsWithColorNoSound("Where would you like to go?\n ", Color.WHITE);
                        setAttemptCount(0);
                    }
                }
                break;
            } catch (InterruptedException | IOException e) {
                e.printStackTrace();
            }
        }

Answer 1

您在 changeRoom 中有一个参数也名为 attemptCount。当您在方法体中引用 attemptCount 时，您指的是参数而不是成员变量。您可以通过更改参数名称、更改变量名称或在您指的是成员变量而不是参数时使用 this.attemptCount 来修复它。

Answer 2

“变量 attemptCount 未在本地声明”

实际上是，作为方法参数：

public void changeRoom(boolean isValidInput, String[] input, int attemptCount)

因此，即使在本地递增，它的值也不会返回给调用代码，因为它没有作为引用传递 - 参见：Is Java “pass-by-reference” or “pass-by-value”?

计数器未递增 Java

Counter not incrementing in Java

java

increment