如何从 oracle sql 中的最大日期获取年份

Question

我正在尝试从下面的查询中获取 yyyy 如果我尝试使用

它会抛出错误

查询

WITH last_startdate
     AS (SELECT owner,
                package_name,
                Max(start_date) MAX_START_DATE,
                to_date(max(start_date),'YYYY') as max_start_date_yr
         FROM   (SELECT DISTINCT owner,
                                 object_name AS PACKAGE_NAME
                 FROM   dba_procedures

                ) P
                JOIN SCHEMA.table_name A /*AUDITING TABLE*/
                  ON P.package_name = A.task_name
         GROUP  BY P.owner,
                   P.package_name)
SELECT *
FROM   last_startdate
ORDER  BY 3 DESC

错误

ORA-01830: date format picture ends before converting entire input string
01830. 00000 -  "date format picture ends before converting entire input string"
*Cause:    
*Action:

预期结果

OWNER PACKAGE_NAME MAX_START_DATE MAX_START_DATE_YR
STAGE PA_AB_CDS    19.02.2021     2021
EDW   PA_BX_BCS    09.12.2020     2020
MART  PA_WQ_AFD    12.08.2019     2019
CODE  PA_WQ_IOD    23.05.2016     2016

关于获得预期结果的任何建议？

Answer 1

我想

start_date 是 DATE。所以 max(start_date) 也是一个日期。

那你为什么要申请to_date呢？将日期转换为日期？这是没有意义的。你我想要 to_char 而不是

to_char(max(start_date),'YYYY') as max_start_date_yr

这将以字符串形式给出年份。或者只使用 EXTRACT 获取数字年份：

extract(year from max(start_date)) as max_start_date_yr

如何从 oracle sql 中的最大日期获取年份

how to get the year from the max date in oracle sql

sql

oracle

plsql

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