C# 是否有等同于 Python 的东西 random.choices()

Question

我正在尝试根据他们的选择做出选择 weight/probability

这是我在 python:

import random

myChoiceList = ["Attack", "Heal", "Amplify", "Defense"]
myWeights = [70, 0, 15, 15] // % probability = 100% Ex. Attack has 70% of selection

print(random.choices(myChoicelist , weights = myWeights, k = 1))

我想在 C# 中做同样的事情，如何做？ C# 是否有任何类似于 random.choices() 的方法我只知道 random.Next()

*这个 python 代码工作正常 randome.choice 接受（序列，权重，k）序列：值，权重：一个列表，您可以权衡每个值的可能性， k：返回列表的长度，

我希望为 C# 做同样的事情，根据概率选择值

Answer 1

你可以得到random.next(0,100)，然后用简单的switch case什么的选择相关项。您的域将是这样的，[0-70、70-85、85-100]。如果您需要完整代码，请告诉我。

    Random ran = new Random();
    int probability = ran.Next(0, 100);
    string s;
    if (probability == 0)
        s = "Heal";
    else if (probability <= 70)
        s = "Attack";
    else if (probability <= 85)
        s = "Amplify";
    else if (probability <= 100)
        s = "Defense";

Answer 2

C# 中没有像这样内置的东西，但是，添加扩展方法来重新创建相同的基本行为并不难：

static class RandomUtils
{
    public static string Choice(this Random rnd, IEnumerable<string> choices, IEnumerable<int> weights)
    {
        var cumulativeWeight = new List<int>();
        int last = 0;
        foreach (var cur in weights)
        {
            last += cur;
            cumulativeWeight.Add(last);
        }
        int choice = rnd.Next(last);
        int i = 0;
        foreach (var cur in choices)
        {
            if (choice < cumulativeWeight[i])
            {
                return cur;
            }
            i++;
        }
        return null;
    }
}

然后就可以像Python版本一样调用了：

string[] choices = { "Attack", "Heal", "Amplify", "Defense" };
int[] weights = { 70, 0, 15, 15 };

Random rnd = new Random();
Console.WriteLine(rnd.Choice(choices, weights));

C# 是否有等同于 Python 的东西 random.choices()

does C# have something equivalent to Pythons random.choices()

c#

python

unity3d

probability-distribution